Ha! Thanks for thatNo because somehow the recoil goes AROUND the bolt lugs and gets distributed to the recoil lug and action body instead...that's one of the things you and I aren't smart enough to understand, but yet nobody can explain why.
Edd, nobody shoots springsIf you put a spring in the chamber instead of a cartridge, you will have pressure against the bolt lugs and no pressure against the recoil lug.
Agreed, but we are assuming (and so was Kirby Allen) that the cartridge is functioning properly. Assuming this, why Wouldn't recoil be a good determinant of the lug forces experienced?Imagine a 30 carbine round forced into a 223 chamber, bullet is pushed up against the neck area of the chamber....bang....bullet goes no where...primer is blown....gun locks up solid....bullet goes no where.....bolt thrust is sky high.............no perceptible RECOIL....
For every action there is an opposite and equal reaction....ie; recoil is the opposite reaction of a bullet moving.
Clarifying, the recoil is transferred through all the rifle parts into the shoulder through its construction including barrel, reciever threads, bolt LUGS, receiver ABUTMENTS and recoil lug. All rifle parts work together as a mass to transfer recoil to the shoulder.
Clarifying, the recoil is transferred through all the rifle parts into the shoulder through its construction including barrel, reciever threads, bolt LUGS, receiver ABUTMENTS and recoil lug. All rifle parts work together as a mass to transfer recoil to the shoulder.
You might be able to look at recoil as a felt representation of the work that you can get done with the chamber pressure, you can change the tool (bullet) but the muscle behind it will remain the same.
For the forces we are dealing with on the lugs the weight of the bullet does not matter. Think of a balloon. The pressure at any given point on the inside surface is the same as any other. A gas under pressure eqalizes against all the walls. If anyone doesn't understand this then they need to go back to physics 101. That's beyond what we are going to be able to cover here. I and I suspect many others here have made an assumption that we're all at a minimum level here and have a basic understanding of rifles and physics. If I have assumed incorrectly I apologize.I might be missing it, but it doesn't seem that the bullet weight is being used in the equation(but for a few posts). Shouldn't this be a primary variable?
edit: Also, wouldn't recoil be a perfect measurement of the force applied to the lugs?
Are you really wanting a discussion here or just to antagonize and argue? If the former I'm in for the duration. If the later then I'm out on what could be a valuable discussion.No because somehow the recoil goes AROUND the bolt lugs and gets distributed to the recoil lug and action body instead...that's one of the things you and I aren't smart enough to understand, but yet nobody can explain why.
This is incorrect.Except it was stated earlier (I forget by who?) that recoil does NOT transfer thru the bolt lugs and it has ZERO effect on bolt lug setback...
I've been saying since the beginning that it is ALL things working together that contribute to bolt lug set back, not just one simple equation that converts chamber PSI to SQ IN on the bolt face.
Great question. Yes, more lugs would spread the force out. Force/3 is less than force/2. More lug area spreads the load out better to hopefully get it below the yield strength of the lug/receiver material.After taking a few days to get through this, it has been interesting. If you went to more bolt lugs would that be better or going to larger lugs be better to help offset lug setback?
idcwby