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Triggertech spring
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<blockquote data-quote="ntsqd" data-source="post: 2807695" data-attributes="member: 93138"><p>A coil spring is a torsion bar, even when used in a tension or compression application. Stretching or compressing the spring causes the wire to twist. You can see this by drawing a line around the spring down the OD of the wire, and then stretching or compressing it. You will see the line twist as you move the spring away from it's at rest state.</p><p></p><p>What feels like a reduction in force to reassemble a shorter spring is actually the result of a lower pre-load on the spring. Springs are rated in force required to compress it some measured distance. Like lbs./in or N/M or whatever. If you have a 1 lbs./in spring then it requires one pound to compress it one inch. To compress it another inch requires another pound of force. At that point you have 2 lbs. of pre-load on that spring. If you cut the spring shorter by an inch and put it back in that situation that originally had it compressed two inches you'll only need about one pound of force (instead of two lbs.) to re-install it. So the pre-load was reduced by roughly 1/2, but that doesn't mean that the spring has a lower spring rate, just that the pre-load needed is less with the shorter spring. This can be very misleading.</p><p></p><p>Spring rate in a coil spring is calculated by this formula:</p><p><img src="https://i0.wp.com/suspensionsecrets.co.uk/wp-content/uploads/2018/05/equation-2.jpg?w=750&ssl=1" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p>(Blatantly stolen from <a href="https://suspensionsecrets.co.uk/how-to-calculate-coil-or-leaf-spring-rates/" target="_blank">here</a><img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite1" alt=":)" title="Smile :)" loading="lazy" data-shortname=":)" /></p><p>Notice how if you reduce the number of active coils (by cutting the spring) that the magnitude of the whole divisor is reduced. Which means that with fewer coils the spring will be stiffer.</p><p></p><p>A cut spring will have less pre-load when re-installed in the original location and that will lower the initial trigger weight feel, but it now has a slightly higher spring rate. How that translates into actual trigger weight will take more math than I'd guess 80% have the patience for.</p></blockquote><p></p>
[QUOTE="ntsqd, post: 2807695, member: 93138"] A coil spring is a torsion bar, even when used in a tension or compression application. Stretching or compressing the spring causes the wire to twist. You can see this by drawing a line around the spring down the OD of the wire, and then stretching or compressing it. You will see the line twist as you move the spring away from it's at rest state. What feels like a reduction in force to reassemble a shorter spring is actually the result of a lower pre-load on the spring. Springs are rated in force required to compress it some measured distance. Like lbs./in or N/M or whatever. If you have a 1 lbs./in spring then it requires one pound to compress it one inch. To compress it another inch requires another pound of force. At that point you have 2 lbs. of pre-load on that spring. If you cut the spring shorter by an inch and put it back in that situation that originally had it compressed two inches you'll only need about one pound of force (instead of two lbs.) to re-install it. So the pre-load was reduced by roughly 1/2, but that doesn't mean that the spring has a lower spring rate, just that the pre-load needed is less with the shorter spring. This can be very misleading. Spring rate in a coil spring is calculated by this formula: [IMG]https://i0.wp.com/suspensionsecrets.co.uk/wp-content/uploads/2018/05/equation-2.jpg?w=750&ssl=1[/IMG] (Blatantly stolen from [URL='https://suspensionsecrets.co.uk/how-to-calculate-coil-or-leaf-spring-rates/']here[/URL]:) Notice how if you reduce the number of active coils (by cutting the spring) that the magnitude of the whole divisor is reduced. Which means that with fewer coils the spring will be stiffer. A cut spring will have less pre-load when re-installed in the original location and that will lower the initial trigger weight feel, but it now has a slightly higher spring rate. How that translates into actual trigger weight will take more math than I'd guess 80% have the patience for. [/QUOTE]
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