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Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
wind drift????
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<blockquote data-quote="Brent" data-source="post: 31340" data-attributes="member: 99"><p>Flopduster,</p><p>Ian nailed it for you. </p><p></p><p>How did you derive 1.55 MOA? 1.6" / 1.047"?</p><p></p><p>You might find this explanation helpfull if you haven't read it already. <a href="http://www.longrangehunting.com/cgi-bin/ultimatebb.cgi?ubb=get_topic&f=2&t=000621" target="_blank">http://www.longrangehunting.com/cgi-bin/ultimatebb.cgi?ubb=get_topic&f=2&t=000621</a> </p><p></p><p></p><p>DMCI,</p><p></p><p> <BLOCKQUOTE><font size="1" face="Verdana, Helvetica, sans-serif">quote:</font><HR><strong>Chart says 1.4 x 15 = 25 moa. 24moa seems way too big.</strong><HR></BLOCKQUOTE></p><p></p><p>His 1.6" of drift per 1 MPH wind at 440 yards, multiplied by 15 MPH = 24" of drift. </p><p></p><p>The scope correction, as Ian stated, is </p><p>24"/4.40 = 5.45 MOA </p><p></p><p>To be absolutely precise, you'd then divide that 24" by 4.40, then divide by 1.047" for 5.21 MOA.</p><p></p><p>There's only a difference of .25 MOA, or at 440 yards, 1.1" if you don't account for the extra .047" per MOA dialed, so it's now big deal.</p><p></p><p>Double checking your windage correction MOA -</p><p></p><p>1.047" per MOA * 4.40 = 4.61" per MOA at 440 yds.</p><p></p><p>4.61" per MOA * 5.21 MOA = 24" corrected for.</p><p></p><p>Or </p><p></p><p>4.61" per MOA * 5.45 MOA = 25.12" corrected for.</p><p></p><p></p><p>I would guess your wind speed was about 14.25 MPH not 15 MPH. <img src="http://images/icons/grin.gif" alt="" class="fr-fic fr-dii fr-draggable " style="" /> </p><p></p><p>High winds are a bitch at LR! As you can see, every MPH makes a big difference, and the farther out your target, the larger impact it had. </p><p></p><p>Let's all say it together now - High BC bullets at high MV makes me a better shot! <img src="http://images/icons/grin.gif" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p></blockquote><p></p>
[QUOTE="Brent, post: 31340, member: 99"] Flopduster, Ian nailed it for you. How did you derive 1.55 MOA? 1.6" / 1.047"? You might find this explanation helpfull if you haven't read it already. [url="http://www.longrangehunting.com/cgi-bin/ultimatebb.cgi?ubb=get_topic&f=2&t=000621"]http://www.longrangehunting.com/cgi-bin/ultimatebb.cgi?ubb=get_topic&f=2&t=000621[/url] DMCI, <BLOCKQUOTE><font size="1" face="Verdana, Helvetica, sans-serif">quote:</font><HR>[B]Chart says 1.4 x 15 = 25 moa. 24moa seems way too big.[/B]<HR></BLOCKQUOTE> His 1.6" of drift per 1 MPH wind at 440 yards, multiplied by 15 MPH = 24" of drift. The scope correction, as Ian stated, is 24"/4.40 = 5.45 MOA To be absolutely precise, you'd then divide that 24" by 4.40, then divide by 1.047" for 5.21 MOA. There's only a difference of .25 MOA, or at 440 yards, 1.1" if you don't account for the extra .047" per MOA dialed, so it's now big deal. Double checking your windage correction MOA - 1.047" per MOA * 4.40 = 4.61" per MOA at 440 yds. 4.61" per MOA * 5.21 MOA = 24" corrected for. Or 4.61" per MOA * 5.45 MOA = 25.12" corrected for. I would guess your wind speed was about 14.25 MPH not 15 MPH. [img]images/icons/grin.gif[/img] High winds are a bitch at LR! As you can see, every MPH makes a big difference, and the farther out your target, the larger impact it had. Let's all say it together now - High BC bullets at high MV makes me a better shot! [img]images/icons/grin.gif[/img] [/QUOTE]
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