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Spin Drift
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<blockquote data-quote="oldmossy" data-source="post: 857782" data-attributes="member: 44047"><p>I'm going to try and present my question(theory) in the way I presented it to my longrange buddy at work. To which he replied-You're thinking about it wrong, it doesnt work that way.</p><p> </p><p>In a perfect word. No spin drift, and no wind- Your muzzle and scope is lined up perfectly with bullseye at 1000 yards. You fire, and it hits perfect in bullseye.</p><p>Now- Add spin drift. You hit 8-10 inches to right. </p><p> </p><p>Now-It's looks to me like spin drift at 100 yds should be 1 inch. 2" at 200 and so on.</p><p> </p><p>So if I were to adjust my scope to perfect at 100 or 200 or 300 or whatever, I would be adjusted for spin drift out to whatever distance. In my mind, spin drift to the right begins the moment the bullet leaves the barrel. So when I sight in my rifle, I've already compensated for spin drift.</p><p> </p><p>But I'm under the impression it doesn't work that way, because the spin of the bullet doesn't slow down as fast as the speed of the bullet(fps). Which translates to the bullet having more time to drift right because it isn't covering as much ground as it does closer to muzzle.</p><p> </p><p>That's where my original question came from. </p><p> </p><p>Looks to me if I sighted in 1/2 inch left at 200(which is what my buddy told me to do also) I would be overcorrecting for the spin drift, and would actually hit 5" left at 1000.</p><p> </p><p>I personally see my impacts are right of my point of aim when I shoot 1000, and I am dead on at 200. I'm just trying to get a feel for at what point this spin drift needs to be compensated for. </p><p> </p><p>I'll check out that ballistics chart you guys mentioned.</p></blockquote><p></p>
[QUOTE="oldmossy, post: 857782, member: 44047"] I'm going to try and present my question(theory) in the way I presented it to my longrange buddy at work. To which he replied-You're thinking about it wrong, it doesnt work that way. In a perfect word. No spin drift, and no wind- Your muzzle and scope is lined up perfectly with bullseye at 1000 yards. You fire, and it hits perfect in bullseye. Now- Add spin drift. You hit 8-10 inches to right. Now-It's looks to me like spin drift at 100 yds should be 1 inch. 2" at 200 and so on. So if I were to adjust my scope to perfect at 100 or 200 or 300 or whatever, I would be adjusted for spin drift out to whatever distance. In my mind, spin drift to the right begins the moment the bullet leaves the barrel. So when I sight in my rifle, I've already compensated for spin drift. But I'm under the impression it doesn't work that way, because the spin of the bullet doesn't slow down as fast as the speed of the bullet(fps). Which translates to the bullet having more time to drift right because it isn't covering as much ground as it does closer to muzzle. That's where my original question came from. Looks to me if I sighted in 1/2 inch left at 200(which is what my buddy told me to do also) I would be overcorrecting for the spin drift, and would actually hit 5" left at 1000. I personally see my impacts are right of my point of aim when I shoot 1000, and I am dead on at 200. I'm just trying to get a feel for at what point this spin drift needs to be compensated for. I'll check out that ballistics chart you guys mentioned. [/QUOTE]
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