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Hunting
Extreme Long Range Hunting & Shooting (ELR)
Scope power for 1,760y ?
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<blockquote data-quote="del2les" data-source="post: 1575717" data-attributes="member: 9299"><p>Uhhh... wrong. Angular measurements do not work that way. I explained the target perception above and the basic math to calculate the required increase in scope magnification to achieve equal perception in the scope and the reticle.</p><p></p><p>As the distance increases, the magnification to maintain the same optic perception on an moa sized target must increase in the same proportion. I.e. 1x, 5x, 10x, 17.6x and so on. Thus for simplification, I used a 1 moa target at 100 yds with a 1x mag setting. Simple math calc for any 1 moa target at the corresponding change in distance. 500, 1,000, 1,760, 2,000 etc. In other words, a 1moa target at 1,000 yds (10") with a 10x scope is the same view as a 1 moa target at 100 yds with a 1x scope. Same for a 1 moa target at 1,760 with an 18x scope, and a1 moa at 2,000 is 20x.</p><p></p><p>So, unless one enjoys shooting at 1 moa dots at 100 yds with a 1x scope, that is the view you have at 1,760 yds with an 18x scope on a 1 moa target (18"). A smaller scope magnification at this range and target size would be similar to sighting at 100 yds at a 1 moa dot with a 3/4x scope or similar.</p><p></p><p>Since most of us do not like sighting or zeroing at 1 moa dots at 100 yds with only 1x scopes, for most of us, we use higher magnifications at 100 yds and thus logic the same at 1 mile on an moa target.</p><p></p><p>This is a basic math calc for angular measurement at increasing distances.</p><p>A 14x scope view at 100 yds on a 1 moa dot to "appear the same relative size" on a 1 moa target at 1,760 yds requires: 14 x 17.6= 246</p></blockquote><p></p>
[QUOTE="del2les, post: 1575717, member: 9299"] Uhhh... wrong. Angular measurements do not work that way. I explained the target perception above and the basic math to calculate the required increase in scope magnification to achieve equal perception in the scope and the reticle. As the distance increases, the magnification to maintain the same optic perception on an moa sized target must increase in the same proportion. I.e. 1x, 5x, 10x, 17.6x and so on. Thus for simplification, I used a 1 moa target at 100 yds with a 1x mag setting. Simple math calc for any 1 moa target at the corresponding change in distance. 500, 1,000, 1,760, 2,000 etc. In other words, a 1moa target at 1,000 yds (10") with a 10x scope is the same view as a 1 moa target at 100 yds with a 1x scope. Same for a 1 moa target at 1,760 with an 18x scope, and a1 moa at 2,000 is 20x. So, unless one enjoys shooting at 1 moa dots at 100 yds with a 1x scope, that is the view you have at 1,760 yds with an 18x scope on a 1 moa target (18"). A smaller scope magnification at this range and target size would be similar to sighting at 100 yds at a 1 moa dot with a 3/4x scope or similar. Since most of us do not like sighting or zeroing at 1 moa dots at 100 yds with only 1x scopes, for most of us, we use higher magnifications at 100 yds and thus logic the same at 1 mile on an moa target. This is a basic math calc for angular measurement at increasing distances. A 14x scope view at 100 yds on a 1 moa dot to "appear the same relative size" on a 1 moa target at 1,760 yds requires: 14 x 17.6= 246 [/QUOTE]
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Scope power for 1,760y ?
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