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Rifles, Reloading, Optics, Equipment
Long Range Scopes and Other Optics
NP-R2 Range Estimation
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<blockquote data-quote="Brent" data-source="post: 15434" data-attributes="member: 99"><p>Here is a quick check I did the other day to make sure my brain was still functioning properly. </p><p>I used the 5.5-22 R2 to range a 5-inch object. I ranged it using a laser and the R2 and found to be 52 yards.</p><p></p><p>The math;</p><p></p><p>(22x) Half target size/ number of lines…or….2.5"/4.8 lines = 52 yards </p><p></p><p>(11x) Same formula, except you divide the result by the same amount the power used is divided by. </p><p></p><p>22/11 = 2</p><p>22/5.5 = 4 etc, etc.</p><p></p><p>(11x) would be 2.5"/2.4 = 10.416/2 = 52 yards</p><p></p><p>(5.5x) would be 2.5"/1.2 = 2.083/4 = 52 yards</p><p></p><p>This means if you are ranging at 3.5x on your mil-dot, 15x divided by 3.5x = 4.2857.</p><p></p><p>Now you can expect the target to measure 4.29 times the mils than what it would at 15x.</p><p></p><p>If it measured 1 mil (3.44 moa) at 15x, I am sure you will see it as 4.3 mils (14.75 moa)at 3.5x, not even close to 10 moa as they suggest.</p><p></p><p>At 5x, I come up with 10.32 moa spacing. </p><p></p><p>If 15x equals 1 mil or 3.44 moa, 15x is three times what 5x is, so 3 * 3.44 = 10.32 moa.</p><p></p><p>This is why 3.5x = 14.74 moa spacing.</p><p></p><p>Hope that clarifies things a bit.</p><p></p><p>[ 02-24-2003: Message edited by: Brent ]</p></blockquote><p></p>
[QUOTE="Brent, post: 15434, member: 99"] Here is a quick check I did the other day to make sure my brain was still functioning properly. I used the 5.5-22 R2 to range a 5-inch object. I ranged it using a laser and the R2 and found to be 52 yards. The math; (22x) Half target size/ number of lines…or….2.5”/4.8 lines = 52 yards (11x) Same formula, except you divide the result by the same amount the power used is divided by. 22/11 = 2 22/5.5 = 4 etc, etc. (11x) would be 2.5”/2.4 = 10.416/2 = 52 yards (5.5x) would be 2.5”/1.2 = 2.083/4 = 52 yards This means if you are ranging at 3.5x on your mil-dot, 15x divided by 3.5x = 4.2857. Now you can expect the target to measure 4.29 times the mils than what it would at 15x. If it measured 1 mil (3.44 moa) at 15x, I am sure you will see it as 4.3 mils (14.75 moa)at 3.5x, not even close to 10 moa as they suggest. At 5x, I come up with 10.32 moa spacing. If 15x equals 1 mil or 3.44 moa, 15x is three times what 5x is, so 3 * 3.44 = 10.32 moa. This is why 3.5x = 14.74 moa spacing. Hope that clarifies things a bit. [ 02-24-2003: Message edited by: Brent ] [/QUOTE]
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NP-R2 Range Estimation
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