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Rifles, Reloading, Optics, Equipment
Long Range Scopes and Other Optics
Mil Ranging story
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<blockquote data-quote="David P. Herne" data-source="post: 16788" data-attributes="member: 29"><p>Ian,</p><p>Sorry to bother you with such low level questions. But I'm gonna be hunting on a ranch this January for Blackbuck antelope where 800-1000 yard shots will most probably be presenting themselves. Unfortunately for me, my laser rangefinder isn't gonna tell me anything about targets standing out beyond 600 yards. On the other hand, the rifle with which I'll be hunting is equipped with the 16X Leupold Mark IV scope (and yes, it has a Mil-Dot reticle).</p><p></p><p>So assuming that the distance between the top of the avg. Blackbuck antelope's back and the very underside of it's chest measures 16" (0.45 yards) and this part of his torso fills in 1/2 the distance between two dots in my reticle, then the animal is 900 yards out. Right? I calculated this by the simple equation of multiplying the height of the target in yards (16" = 0.45 yds) by 1000, and then dividing by the target's height in milliradians (0.5).</p><p></p><p>Also, what it the margin of error in this ranging method, especially given that the scope is only 16X and the target is pretty **** small. In other words, what's to prevent a 16" target that is ostensibly around 900 yards out, appearing to one man (through a 16X scope) as spaning 1/2 the distance between two mil-dots, while appearing to another man, as spanning 1/3 or perhaps 2/3 of the distance between two mil-dots?</p><p></p><p>Regards,</p><p>Dave</p></blockquote><p></p>
[QUOTE="David P. Herne, post: 16788, member: 29"] Ian, Sorry to bother you with such low level questions. But I'm gonna be hunting on a ranch this January for Blackbuck antelope where 800-1000 yard shots will most probably be presenting themselves. Unfortunately for me, my laser rangefinder isn't gonna tell me anything about targets standing out beyond 600 yards. On the other hand, the rifle with which I'll be hunting is equipped with the 16X Leupold Mark IV scope (and yes, it has a Mil-Dot reticle). So assuming that the distance between the top of the avg. Blackbuck antelope's back and the very underside of it's chest measures 16" (0.45 yards) and this part of his torso fills in 1/2 the distance between two dots in my reticle, then the animal is 900 yards out. Right? I calculated this by the simple equation of multiplying the height of the target in yards (16" = 0.45 yds) by 1000, and then dividing by the target's height in milliradians (0.5). Also, what it the margin of error in this ranging method, especially given that the scope is only 16X and the target is pretty **** small. In other words, what's to prevent a 16" target that is ostensibly around 900 yards out, appearing to one man (through a 16X scope) as spaning 1/2 the distance between two mil-dots, while appearing to another man, as spanning 1/3 or perhaps 2/3 of the distance between two mil-dots? Regards, Dave [/QUOTE]
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Mil Ranging story
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