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Hunting
Long Range Hunting & Shooting
Does recoil begin before the bullet exits the muzzle?
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<blockquote data-quote="ATH" data-source="post: 1672872" data-attributes="member: 1656"><p>One can factually demonstrate that the barrel dwell time stated earlier of 0.0007 seconds is ballpark correct. 3000fps and a 24" barrel yields 0.000667 seconds.</p><p></p><p>Remember that the inertia of the rifle must be taken into account. Since it is much heavier than the bullet, it will accelerate more slowly in proportion to the difference in mass.</p><p></p><p>Let's take a 3.5kg rifle shooting a 200gr bullet with 72gr of powder (so 17.5 grams total ejection mass) at 3000fps (914.4m/s). </p><p>- The rifle is 200X heavier than the ejection mass (3500/17.5=200). </p><p>- The bullet accelerates from 0 to 914.4m/s in 0.000667 seconds, so it's acceleration is 914.4/0.000667 = 1,370,914 m/s^2. Making an assumption that the acceleration is constant (close enough for this exercise).</p><p>- The rifle is 200X heavier, so its acceleration is 1,370,914/200 = 6854.6 m/s^2</p><p>- The distance the rifle travels is Distance = 1/2 X Acceleration X Time^2, so .5 X 6854.6 X 0.000667^2 = 0.0015 meters, or .06 inches</p><p></p><p>This 0.06 inches does not account for any friction forces from a rest; in that case movement would be even less.</p><p></p><p>I would be looking towards how each rest system is stressing the rifle differently versus the gun moving while the bullet is in the barrel as the cause of what you observe.</p></blockquote><p></p>
[QUOTE="ATH, post: 1672872, member: 1656"] One can factually demonstrate that the barrel dwell time stated earlier of 0.0007 seconds is ballpark correct. 3000fps and a 24” barrel yields 0.000667 seconds. Remember that the inertia of the rifle must be taken into account. Since it is much heavier than the bullet, it will accelerate more slowly in proportion to the difference in mass. Let’s take a 3.5kg rifle shooting a 200gr bullet with 72gr of powder (so 17.5 grams total ejection mass) at 3000fps (914.4m/s). - The rifle is 200X heavier than the ejection mass (3500/17.5=200). - The bullet accelerates from 0 to 914.4m/s in 0.000667 seconds, so it’s acceleration is 914.4/0.000667 = 1,370,914 m/s^2. Making an assumption that the acceleration is constant (close enough for this exercise). - The rifle is 200X heavier, so its acceleration is 1,370,914/200 = 6854.6 m/s^2 - The distance the rifle travels is Distance = 1/2 X Acceleration X Time^2, so .5 X 6854.6 X 0.000667^2 = 0.0015 meters, or .06 inches This 0.06 inches does not account for any friction forces from a rest; in that case movement would be even less. I would be looking towards how each rest system is stressing the rifle differently versus the gun moving while the bullet is in the barrel as the cause of what you observe. [/QUOTE]
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Does recoil begin before the bullet exits the muzzle?
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