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<blockquote data-quote="Hugnot" data-source="post: 2504817" data-attributes="member: 115658"><p>Coriolis effect? TOF? How much can your target, fixed to the surface of a spinning planet, move under a flying bullet in 1.38 seconds? TOF @ 1000, 6.5 147 gr. ELDM @ 2850 fps MV..</p><p></p><p>The latitude of the shot is important. At the equator the rotational speed of planet earth is about 1,000 mph. The rocket guys like to launch their big projectiles near the equator, taking advantage of higher angular momentum.</p><p></p><p>Taking a look at the Hornady 4DOF program, windage values at zero wind speed, shooting a 6.5 147gr HELDM bullet at 2,850 fps. The deflection at the North Pole would be .55 MOA for a shot in any direction, at 45 degrees (mid Oregon), the deflection would be .77 MOA at any direction, at the equator the deflection would be .86 MOA for a shot in any direction. .86 MOA (equator) - .55 MOA(north pole) = .31 MOA or 3.1 inches at 1,000. The elevation at 45 degrees latitude (like Oregon) shooting directly north up 24.48 MOA, shooting east 90 deg. up 24.29, west 270 deg. up 24.66. >> 24.66 - 24.29 = .37 MOA or 3.7 inches elevation difference at 1000, enough to miss X ring.</p><p></p><p>A mil rad at 100 > 36 inches per yard X 100 = 3600/1000 = 3.6 inches at 100 > 10 times more or 36 inches at 1000. Having 1/10 mrad elevation dial clicks this would be one click or 36 X .1 = 3.6 inches.</p><p></p><p>I like the tall target, like getting a group to hit at a plumb line making an elevation to hit at 1000, thinking that any existing wind affects would be more important than the Coriolis effect, provided the target was closer than several miles away. I like zippy bullets & most of my targets are less than 600 yards distant.</p></blockquote><p></p>
[QUOTE="Hugnot, post: 2504817, member: 115658"] Coriolis effect? TOF? How much can your target, fixed to the surface of a spinning planet, move under a flying bullet in 1.38 seconds? TOF @ 1000, 6.5 147 gr. ELDM @ 2850 fps MV.. The latitude of the shot is important. At the equator the rotational speed of planet earth is about 1,000 mph. The rocket guys like to launch their big projectiles near the equator, taking advantage of higher angular momentum. Taking a look at the Hornady 4DOF program, windage values at zero wind speed, shooting a 6.5 147gr HELDM bullet at 2,850 fps. The deflection at the North Pole would be .55 MOA for a shot in any direction, at 45 degrees (mid Oregon), the deflection would be .77 MOA at any direction, at the equator the deflection would be .86 MOA for a shot in any direction. .86 MOA (equator) - .55 MOA(north pole) = .31 MOA or 3.1 inches at 1,000. The elevation at 45 degrees latitude (like Oregon) shooting directly north up 24.48 MOA, shooting east 90 deg. up 24.29, west 270 deg. up 24.66. >> 24.66 - 24.29 = .37 MOA or 3.7 inches elevation difference at 1000, enough to miss X ring. A mil rad at 100 > 36 inches per yard X 100 = 3600/1000 = 3.6 inches at 100 > 10 times more or 36 inches at 1000. Having 1/10 mrad elevation dial clicks this would be one click or 36 X .1 = 3.6 inches. I like the tall target, like getting a group to hit at a plumb line making an elevation to hit at 1000, thinking that any existing wind affects would be more important than the Coriolis effect, provided the target was closer than several miles away. I like zippy bullets & most of my targets are less than 600 yards distant. [/QUOTE]
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