Forums
New posts
Search forums
What's new
Articles
Latest reviews
Author list
Classifieds
Log in
Register
What's new
Search
Search
Search titles and first posts only
Search titles only
By:
New posts
Search forums
Menu
Log in
Register
Install the app
Install
Forums
Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
Canting - the right answer
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Reply to thread
Message
<blockquote data-quote="JBM" data-source="post: 110287" data-attributes="member: 1969"><p>It looks like my sight height may have been off (probably 1.5"). So here it is again:</p><p></p><p>For 100 yard zero, no cant, I get the following:</p><p></p><p><font class="small">Code:</font><hr /><pre></p><p>Range Drop Drop Windage Windage</p><p>(yds) (in) (moa) (in) (moa)</p><p>0 -2.0 *** 0.0 ***</p><p>100 -0.0 -0.0 0.0 0.0</p><p>200 -2.8 -1.3 0.0 0.0</p><p>300 -11.0 -3.5 0.0 0.0</p><p>400 -25.5 -6.1 0.0 0.0</p><p>500 -47.5 -9.1 0.0 0.0</p><p>600 -78.0 -12.4 0.0 0.0</p><p>700 -118.6 -16.2 0.0 0.0</p><p>800 -171.2 -20.4 0.0 0.0</p><p>900 -237.9 -25.2 0.0 0.0</p><p>1000 -321.3 -30.7 0.0 0.0</p><p></pre><hr /></p><p></p><p>Elevation angle is 3.98 moa.</p><p></p><p>Plugging this into my formula with a 10" cant, I get:</p><p></p><p>Elevation = 3.920 moa</p><p>Azimuth = 0.691 moa</p><p></p><p>Change in Elevation = 3.98 - 3.92 = 0.06 moa or 0.31 inches lower at 500 yards.</p><p></p><p>Change in Azimuth = 0.0 - 0.691 = 0.691 moa or 3.62 inches at 500 yards.</p><p></p><p>My calculated trajectory for a 10 degree cant is:</p><p></p><p><font class="small">Code:</font><hr /><pre></p><p>Range Drop Drop Windage Windage</p><p>(yds) (in) (moa) (in) (moa)</p><p>0 -2.0 *** -0.3 ***</p><p>100 -0.0 -0.0 0.4 0.4</p><p>200 -2.8 -1.4 1.1 0.5</p><p>300 -11.1 -3.5 1.8 0.6</p><p>400 -25.8 -6.1 2.5 0.6</p><p>500 -47.7 -9.1 3.3 0.6</p><p>600 -78.3 -12.5 4.0 0.6</p><p>700 -119.0 -16.2 4.7 0.6</p><p>800 -171.7 -20.5 5.4 0.6</p><p>900 -238.4 -25.3 6.2 0.7</p><p>1000 -321.9 -30.7 6.9 0.7</p><p></pre><hr /></p><p></p><p>This shows the calculated drop to be 47.7" and windage to be 3.3 - -0.3 = 3.6" which agrees well with the values calculated from the formula.</p><p></p><p>For a 1000 yard zero, I get the following trajectory:</p><p></p><p><font class="small">Code:</font><hr /><pre></p><p>Range Drop Drop Windage Windage</p><p>(yds) (in) (moa) (in) (moa)</p><p>0 -2.0 *** 0.0 *** </p><p>100 32.1 30.7 0.0 0.0 </p><p>200 61.5 29.4 0.0 0.0 </p><p>300 85.4 27.2 0.0 0.0 </p><p>400 103.0 24.6 0.0 0.0 </p><p>500 113.2 21.6 0.0 0.0 </p><p>600 114.8 18.3 0.0 0.0 </p><p>700 106.3 14.5 0.0 0.0 </p><p>800 85.8 10.2 0.0 0.0 </p><p>900 51.3 5.4 0.0 0.0 </p><p>1000 -0.0 -0.0 0.0 0.0 </p><p></pre><hr /></p><p></p><p>With an elevation angle of 34.66 moa.</p><p></p><p>Plugging these into my formulas for a 10 degree cant, I get:</p><p></p><p>Elevation = 34.133 moa</p><p>Azimuth = 6.019 moa</p><p></p><p>Change in elevation is 34.66 - 34.133 = 0.527 moa or 2.76" at 500 yards.</p><p></p><p>Change in azimuth is 6.019 moa (started out at zero) or 31.52" at 500 yards.</p><p></p><p>My calculated trajectory with a 10 degree cant and 1000 yard zero is:</p><p></p><p><font class="small">Code:</font><hr /><pre></p><p>Range Drop Drop Windage Windage</p><p>(yds) (in) (moa) (in) (moa)</p><p>0 -2.0 *** -0.3 ***</p><p>100 31.6 30.2 6.0 5.7</p><p>200 60.4 28.9 12.3 5.9</p><p>300 83.8 26.7 18.6 5.9</p><p>400 100.8 24.1 24.9 5.9</p><p>500 110.5 21.1 31.2 6.0</p><p>600 111.5 17.8 37.5 6.0</p><p>700 102.5 14.0 43.8 6.0</p><p>800 81.5 9.7 50.1 6.0</p><p>900 46.3 4.9 56.4 6.0</p><p>1000 -5.5 -0.5 62.7 6.0</p><p></pre><hr /></p><p></p><p>The difference in drop from the trajectories is 2.7" and for windage 31.2 - (-0.3) = 31.5".</p><p></p><p>Both agree very closely with the values calculated from my formula.</p><p></p><p>Gustavo -- what are the values you are getting? I see the final drop and windage, but what are the changes? What did you get for a change in drop and windage using your formula? That's what we ought to be comparing. That way we can eliminate the differences in the trajectory calculations.</p></blockquote><p></p>
[QUOTE="JBM, post: 110287, member: 1969"] It looks like my sight height may have been off (probably 1.5"). So here it is again: For 100 yard zero, no cant, I get the following: <font class="small">Code:</font><hr /><pre> Range Drop Drop Windage Windage (yds) (in) (moa) (in) (moa) 0 -2.0 *** 0.0 *** 100 -0.0 -0.0 0.0 0.0 200 -2.8 -1.3 0.0 0.0 300 -11.0 -3.5 0.0 0.0 400 -25.5 -6.1 0.0 0.0 500 -47.5 -9.1 0.0 0.0 600 -78.0 -12.4 0.0 0.0 700 -118.6 -16.2 0.0 0.0 800 -171.2 -20.4 0.0 0.0 900 -237.9 -25.2 0.0 0.0 1000 -321.3 -30.7 0.0 0.0 </pre><hr /> Elevation angle is 3.98 moa. Plugging this into my formula with a 10" cant, I get: Elevation = 3.920 moa Azimuth = 0.691 moa Change in Elevation = 3.98 - 3.92 = 0.06 moa or 0.31 inches lower at 500 yards. Change in Azimuth = 0.0 - 0.691 = 0.691 moa or 3.62 inches at 500 yards. My calculated trajectory for a 10 degree cant is: <font class="small">Code:</font><hr /><pre> Range Drop Drop Windage Windage (yds) (in) (moa) (in) (moa) 0 -2.0 *** -0.3 *** 100 -0.0 -0.0 0.4 0.4 200 -2.8 -1.4 1.1 0.5 300 -11.1 -3.5 1.8 0.6 400 -25.8 -6.1 2.5 0.6 500 -47.7 -9.1 3.3 0.6 600 -78.3 -12.5 4.0 0.6 700 -119.0 -16.2 4.7 0.6 800 -171.7 -20.5 5.4 0.6 900 -238.4 -25.3 6.2 0.7 1000 -321.9 -30.7 6.9 0.7 </pre><hr /> This shows the calculated drop to be 47.7" and windage to be 3.3 - -0.3 = 3.6" which agrees well with the values calculated from the formula. For a 1000 yard zero, I get the following trajectory: <font class="small">Code:</font><hr /><pre> Range Drop Drop Windage Windage (yds) (in) (moa) (in) (moa) 0 -2.0 *** 0.0 *** 100 32.1 30.7 0.0 0.0 200 61.5 29.4 0.0 0.0 300 85.4 27.2 0.0 0.0 400 103.0 24.6 0.0 0.0 500 113.2 21.6 0.0 0.0 600 114.8 18.3 0.0 0.0 700 106.3 14.5 0.0 0.0 800 85.8 10.2 0.0 0.0 900 51.3 5.4 0.0 0.0 1000 -0.0 -0.0 0.0 0.0 </pre><hr /> With an elevation angle of 34.66 moa. Plugging these into my formulas for a 10 degree cant, I get: Elevation = 34.133 moa Azimuth = 6.019 moa Change in elevation is 34.66 - 34.133 = 0.527 moa or 2.76" at 500 yards. Change in azimuth is 6.019 moa (started out at zero) or 31.52" at 500 yards. My calculated trajectory with a 10 degree cant and 1000 yard zero is: <font class="small">Code:</font><hr /><pre> Range Drop Drop Windage Windage (yds) (in) (moa) (in) (moa) 0 -2.0 *** -0.3 *** 100 31.6 30.2 6.0 5.7 200 60.4 28.9 12.3 5.9 300 83.8 26.7 18.6 5.9 400 100.8 24.1 24.9 5.9 500 110.5 21.1 31.2 6.0 600 111.5 17.8 37.5 6.0 700 102.5 14.0 43.8 6.0 800 81.5 9.7 50.1 6.0 900 46.3 4.9 56.4 6.0 1000 -5.5 -0.5 62.7 6.0 </pre><hr /> The difference in drop from the trajectories is 2.7" and for windage 31.2 - (-0.3) = 31.5". Both agree very closely with the values calculated from my formula. Gustavo -- what are the values you are getting? I see the final drop and windage, but what are the changes? What did you get for a change in drop and windage using your formula? That's what we ought to be comparing. That way we can eliminate the differences in the trajectory calculations. [/QUOTE]
Insert quotes…
Verification
Post reply
Forums
Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
Canting - the right answer
Top