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Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
Bullet stabilization, strictly RPM?
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<blockquote data-quote="devildoc" data-source="post: 170588" data-attributes="member: 5615"><p>Well I'm not familiar with all of the units that Mikecr was using but I think I got the gist of what he was saying, and agree with it. So I'll take a stab at breaking it down barney-style</p><p>Basically displacement per turn shows the relationship between how much gyroscopic stabilization there is for how much drag there is. </p><p></p><p>Since we're dealing with a projectile that has a center of drag in front of the center of mass we must have more gyroscopic stabilization than drag force, which will cause the bullet to "tumble" or destabilize. </p><p></p><p>Since how much air the projectile displaced is proportional to the drag, and how fast it's spinning is proportional to it's gyroscopic stabilization, how much air the projectile displaces in relation to one revolution tells us whether the projectile is stabilized or not. </p><p></p><p>So, what that means is, the further from the center of drag the center of mass is (longer bullet), and the faster we push the projectile (more displacement/drag), or the higher the amount of drag on the nose of the bullet (frictional coefficient), the faster the bullet must be spun to stabilize it.</p><p></p><p>I think I got it right but if someone wants to correct me, please do.</p><p>(had to edit a couple times before it looked like my thoughts came out right)</p></blockquote><p></p>
[QUOTE="devildoc, post: 170588, member: 5615"] Well I'm not familiar with all of the units that Mikecr was using but I think I got the gist of what he was saying, and agree with it. So I'll take a stab at breaking it down barney-style Basically displacement per turn shows the relationship between how much gyroscopic stabilization there is for how much drag there is. Since we're dealing with a projectile that has a center of drag in front of the center of mass we must have more gyroscopic stabilization than drag force, which will cause the bullet to "tumble" or destabilize. Since how much air the projectile displaced is proportional to the drag, and how fast it's spinning is proportional to it's gyroscopic stabilization, how much air the projectile displaces in relation to one revolution tells us whether the projectile is stabilized or not. So, what that means is, the further from the center of drag the center of mass is (longer bullet), and the faster we push the projectile (more displacement/drag), or the higher the amount of drag on the nose of the bullet (frictional coefficient), the faster the bullet must be spun to stabilize it. I think I got it right but if someone wants to correct me, please do. (had to edit a couple times before it looked like my thoughts came out right) [/QUOTE]
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Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
Bullet stabilization, strictly RPM?
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