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Bubble level for rifle
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<blockquote data-quote="4mesh063" data-source="post: 40999" data-attributes="member: 941"><p><BLOCKQUOTE><font size="1" face="Verdana, Helvetica, sans-serif">quote:</font><HR>Not let's figure the same for a zero of 600 yards. I'll guess you use a magnum and that your 600 yard zero is about 11 MOA (sea level) ON TOP of your 100 yard zero (a hidden ~3 MOA). You can see that if you perform the 100 yard "round robin" test again your "cone base" circle is going to be at least ~22 MOA plus the "hidden" 100 yard zero correction of ~3 MOA (but 6 MOA of "cone base"). Overall I'd say you would have a circle of about 28 MOA.</p><p> <HR></BLOCKQUOTE></p><p></p><p>Dave, </p><p></p><p>28 moa, And you may well, but, </p><p>You keep refering to bullet path as drop. I realise that different software uses different terms. I call drop, drop. How much does the bullet fall from the bore line. I call bullet path, how much does it fall from the point of aim. </p><p></p><p>Your calculations will be infinitly easier to do and for others to understand if you use the drop value instead of path. This way, a zero at 600 yards is a zero at 600 yards. Zero is zero. Not a recalculation from some 100 yard zero. Take the drop total, multiply by 2 for when you rotate the gun 180 degrees, and subtract twice the sight height becuase the scope is now the datum and the barrel is now 3.5" higher from where it was. (This excluding the few thousanths of scope incline we have)</p><p></p><p>When I made my scope mounts on my gun, I put the action in the mill vise and put a .030 shim under one side. Then milled the ring channels. It's a Kurt vise and is roughly 5" wide on the bed. I get .030 of incline for every 5" of barrel length. (less the sag). Now, at the end of a 25" barrel(average of 24"/26" factory barrels) , there would be 5x.030 or .150 of additional bore height to subtract from the sight height. I wonder if they are not doing something with that as well. There are simply too many different ways to come up with an answer without establishing some standards for where to measure from. Some are nearly impossible to visualize as they rotate around because so many different errors affect the result in differnt directions. Even in my example above of 25", where are we measuring from. The middle of the scope tube between the rings, or at the objective lens. Where do we consider the muzzle to be, at the muzzle, or the bolt raceway area under the 1.75" sight height because the sight height at the true muzzle is less than it is where we measured it at the action.</p><p></p><p>You picked on me for not looking at the numbers 80"-78" to 3 decimals when I only pointed out the location of the variation... Go ahead and now calculate the sight height to the millionth. You can see where this is going, I have no idea what they are using as a baseline reference for thier data, but there is probably some good reason for the change in numbers.</p></blockquote><p></p>
[QUOTE="4mesh063, post: 40999, member: 941"] <BLOCKQUOTE><font size="1" face="Verdana, Helvetica, sans-serif">quote:</font><HR>Not let's figure the same for a zero of 600 yards. I'll guess you use a magnum and that your 600 yard zero is about 11 MOA (sea level) ON TOP of your 100 yard zero (a hidden ~3 MOA). You can see that if you perform the 100 yard "round robin" test again your "cone base" circle is going to be at least ~22 MOA plus the "hidden" 100 yard zero correction of ~3 MOA (but 6 MOA of "cone base"). Overall I'd say you would have a circle of about 28 MOA. <HR></BLOCKQUOTE> Dave, 28 moa, And you may well, but, You keep refering to bullet path as drop. I realise that different software uses different terms. I call drop, drop. How much does the bullet fall from the bore line. I call bullet path, how much does it fall from the point of aim. Your calculations will be infinitly easier to do and for others to understand if you use the drop value instead of path. This way, a zero at 600 yards is a zero at 600 yards. Zero is zero. Not a recalculation from some 100 yard zero. Take the drop total, multiply by 2 for when you rotate the gun 180 degrees, and subtract twice the sight height becuase the scope is now the datum and the barrel is now 3.5" higher from where it was. (This excluding the few thousanths of scope incline we have) When I made my scope mounts on my gun, I put the action in the mill vise and put a .030 shim under one side. Then milled the ring channels. It's a Kurt vise and is roughly 5" wide on the bed. I get .030 of incline for every 5" of barrel length. (less the sag). Now, at the end of a 25" barrel(average of 24"/26" factory barrels) , there would be 5x.030 or .150 of additional bore height to subtract from the sight height. I wonder if they are not doing something with that as well. There are simply too many different ways to come up with an answer without establishing some standards for where to measure from. Some are nearly impossible to visualize as they rotate around because so many different errors affect the result in differnt directions. Even in my example above of 25", where are we measuring from. The middle of the scope tube between the rings, or at the objective lens. Where do we consider the muzzle to be, at the muzzle, or the bolt raceway area under the 1.75" sight height because the sight height at the true muzzle is less than it is where we measured it at the action. You picked on me for not looking at the numbers 80"-78" to 3 decimals when I only pointed out the location of the variation... Go ahead and now calculate the sight height to the millionth. You can see where this is going, I have no idea what they are using as a baseline reference for thier data, but there is probably some good reason for the change in numbers. [/QUOTE]
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