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Rifles, Reloading, Optics, Equipment
Long Range Scopes and Other Optics
B&C Leupold Question
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<blockquote data-quote="sscoyote" data-source="post: 746796" data-attributes="member: 1133"><p>Take the large bullet drop and divide by the SBD of every value [from DV's link posted above], and that will give you the percentage of magnification change and avg. magnification change [by multiplying that value by 8 power] since subtension is inversely proportional to magnification. I've never quite trusted the magnification markings on the Leupold power rings though--since the range estimating systems are a bit off for power calculations. They're actually never perfect though since actual magnification and the marked magnification is not exact. The calcs are usually very close though...somehow.</p></blockquote><p></p>
[QUOTE="sscoyote, post: 746796, member: 1133"] Take the large bullet drop and divide by the SBD of every value [from DV's link posted above], and that will give you the percentage of magnification change and avg. magnification change [by multiplying that value by 8 power] since subtension is inversely proportional to magnification. I've never quite trusted the magnification markings on the Leupold power rings though--since the range estimating systems are a bit off for power calculations. They're actually never perfect though since actual magnification and the marked magnification is not exact. The calcs are usually very close though...somehow. [/QUOTE]
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B&C Leupold Question
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