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Rifles, Reloading, Optics, Equipment
Reloading
Advice on bullet seating depth Berger 95 grain hybrid
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<blockquote data-quote="merbeau" data-source="post: 773297" data-attributes="member: 38494"><p><span style="font-family: 'Arial'"><span style="font-size: 18px"><span style="font-size: 12px"><span style="color: black"><span style="font-family: 'Times New Roman'">Level-head and Freedom2live</span></span></span></span></span></p><p> <span style="font-family: 'Arial'"><span style="font-size: 18px"></span></span></p><p><span style="font-family: 'Arial'"><span style="font-size: 18px"><span style="color: black"><span style="font-family: 'Times New Roman'"><span style="font-size: 12px">Thank you for replying. I measured the COL to the tip and not the ogive.</span></span></span></span></span></p><p> <span style="font-family: 'Arial'"><span style="font-size: 18px"></span></span></p><p><span style="font-family: 'Arial'"><span style="font-size: 18px"><span style="color: black"><span style="font-family: 'Times New Roman'"><span style="font-size: 12px">The statistics on the Nosler brass was remarkable. Less than 1.0 grain difference between maximum and minimum and 90% within 0.3 grains of each other. </span></span></span></span></span></p><p> <span style="font-family: 'Arial'"><span style="font-size: 18px"></span></span></p><p><span style="font-family: 'Arial'"><span style="font-size: 18px"><span style="color: black"><span style="font-family: 'Times New Roman'"><span style="font-size: 12px">Another determination and question: </span></span></span></span></span></p><p> <span style="font-family: 'Arial'"><span style="font-size: 18px"></span></span></p><p><span style="font-family: 'Arial'"><span style="font-size: 18px"><span style="color: black"><span style="font-family: 'Times New Roman'"><span style="font-size: 12px">For volume I used the water technique and found a mean of 52.0 with a range of 52.2 to 52.3 grains. The volume occupied by the bullet is case length (2.032) and bullet length (1.07) then subtracted the overall COL (2.695) which is 0.407 inches for bullet seating. Next calculate the area of the bullet's cross section. For a .243 diameter bullet, that is (0.2432 ÷ 4) x 3.1416 = 0.0464 square inches. Multiply that area by the seating depth gives you the volume 0.0188 of the case occupied by the bullet, but it is in cubic inches. To convert cubic inches to grains of water, multiply by 252.8 grains of water per cubic inch which is 4.774 grains. Then subtract from case volume 52.0 – 4.774 = 47.23 grains. This a little off because the Berger bullet is a boat tail. </span></span></span></span></span></p><p> <span style="font-family: 'Arial'"><span style="font-size: 18px"></span></span></p><p><span style="font-family: 'Arial'"><span style="font-size: 18px"><span style="color: black"><span style="font-family: 'Times New Roman'"><span style="font-size: 12px">Question: So any charge larger than 47 grains would be compressed? </span></span></span></span></span></p><p><span style="font-family: 'Arial'"><span style="font-size: 18px"></span></span></p></blockquote><p></p>
[QUOTE="merbeau, post: 773297, member: 38494"] [FONT=Arial][SIZE=5][SIZE=3][COLOR=black][FONT=Times New Roman]Level-head and Freedom2live[/FONT][/COLOR][/SIZE] [COLOR=black][FONT=Times New Roman][SIZE=3]Thank you for replying. I measured the COL to the tip and not the ogive.[/SIZE][/FONT][/COLOR] [COLOR=black][FONT=Times New Roman][SIZE=3]The statistics on the Nosler brass was remarkable. Less than 1.0 grain difference between maximum and minimum and 90% within 0.3 grains of each other. [/SIZE][/FONT][/COLOR] [COLOR=black][FONT=Times New Roman][SIZE=3]Another determination and question: [/SIZE][/FONT][/COLOR] [COLOR=black][FONT=Times New Roman][SIZE=3][/SIZE][/FONT][/COLOR] [COLOR=black][FONT=Times New Roman][SIZE=3]For volume I used the water technique and found a mean of 52.0 with a range of 52.2 to 52.3 grains. The volume occupied by the bullet is case length (2.032) and bullet length (1.07) then subtracted the overall COL (2.695) which is 0.407 inches for bullet seating. Next calculate the area of the bullet's cross section. For a .243 diameter bullet, that is (0.2432 ÷ 4) x 3.1416 = 0.0464 square inches. Multiply that area by the seating depth gives you the volume 0.0188 of the case occupied by the bullet, but it is in cubic inches. To convert cubic inches to grains of water, multiply by 252.8 grains of water per cubic inch which is 4.774 grains. Then subtract from case volume 52.0 – 4.774 = 47.23 grains. This a little off because the Berger bullet is a boat tail. [/SIZE][/FONT][/COLOR] [COLOR=black][FONT=Times New Roman][SIZE=3][/SIZE][/FONT][/COLOR] [COLOR=black][FONT=Times New Roman][SIZE=3]Question: So any charge larger than 47 grains would be compressed? [/SIZE][/FONT][/COLOR] [/SIZE][/FONT] [/QUOTE]
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Advice on bullet seating depth Berger 95 grain hybrid
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