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Rifles, Reloading, Optics, Equipment
Reloading
7mm WSM, 180's and Re17
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<blockquote data-quote="MontanaRifleman" data-source="post: 867480" data-attributes="member: 11717"><p>What I do is find the bore diameter area - radius squared times pi</p><p></p><p>.284" x .5 = .142"</p><p></p><p>.142 x .142 = .020164"</p><p></p><p>.020164" x 3.14 (pi) = .0633 square inches = bore area</p><p></p><p></p><p>Then I find the H2O volume which I get from AmmoGuide which is 79.7 for the 7 WSM</p><p></p><p>I divide 79.7 by .0633 = 1258</p><p></p><p>The water volume in Ammoguide includes neck space (I think). Ideally, you want to compare volume of powder space (in water volume, not powder volume) but it gets you close enough for a ballpark idea. This is also a good method for determining potential barrel life.</p><p></p><p>I have been looking at RL33 a lot and 1258 would be borderline good case for for RL33 with heavy bullets. A higher ratio might be better but 1258 could produce good results with heavy bullets.</p></blockquote><p></p>
[QUOTE="MontanaRifleman, post: 867480, member: 11717"] What I do is find the bore diameter area - radius squared times pi .284" x .5 = .142" .142 x .142 = .020164" .020164" x 3.14 (pi) = .0633 square inches = bore area Then I find the H2O volume which I get from AmmoGuide which is 79.7 for the 7 WSM I divide 79.7 by .0633 = 1258 The water volume in Ammoguide includes neck space (I think). Ideally, you want to compare volume of powder space (in water volume, not powder volume) but it gets you close enough for a ballpark idea. This is also a good method for determining potential barrel life. I have been looking at RL33 a lot and 1258 would be borderline good case for for RL33 with heavy bullets. A higher ratio might be better but 1258 could produce good results with heavy bullets. [/QUOTE]
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Rifles, Reloading, Optics, Equipment
Reloading
7mm WSM, 180's and Re17
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