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375-408 CheyTac (Kirby Alert!!!!!!) question
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<blockquote data-quote="Jon A" data-source="post: 120600" data-attributes="member: 319"><p>A couple notes:</p><p></p><p>Some are wondering how the faster bullet slows down faster with the same BC. That's just the way it works. With the same cd the force of drag is proportional to the square of the velocity. If you look at any chart assuming a constant BC, you'll see the bullet loses more velocity in the first 100 yds than it does in the second, more in the second than in the third, etc. That will happen all with the same BC. It's just the way things work. This is why a 200 fps advantage at the muzzle does not equate to a 200 fps advantage downrange--the slower bullet will catch the faster bullet on the velocity vs. distance curve. Keep in mind, that's all with the bullet's drag curve not changing at all.</p><p></p><p>That said, I would like to see some more detailed numbers showing what triggerfifty described. In fact, I'd like to take back the comparison I made earlier. I should have though about that a bit more before posting. </p><p></p><p>With a 200 <strong>fps</strong> advantage at the muzzle, the slower bullet will catch up velocity vs. distance wise (less than 200 fps downrange). But if the muzzle advantage equates to 200 <strong>yds</strong>, I don't see how the slower bullet will catch up <em>distance</em>-wise as much as I stated without a serious change to its drag curve. Sure, it could happen. With a 200 yd head start you shouldn't expect <em>exactly</em> a 200 yd supersonic range advantage...but it should be pretty close unless something odd is happening to the bullet which changes its drag characteristics (overstabilization, not "nosing over" at long ranges, etc).</p><p></p><p>Like I said, it <em>could</em> happen, but I think it would take a serious change to the bullet's drag curve to do it. If triggerfifty has an explanation of how it happens without, I would be very interested to hear it.</p></blockquote><p></p>
[QUOTE="Jon A, post: 120600, member: 319"] A couple notes: Some are wondering how the faster bullet slows down faster with the same BC. That's just the way it works. With the same cd the force of drag is proportional to the square of the velocity. If you look at any chart assuming a constant BC, you'll see the bullet loses more velocity in the first 100 yds than it does in the second, more in the second than in the third, etc. That will happen all with the same BC. It's just the way things work. This is why a 200 fps advantage at the muzzle does not equate to a 200 fps advantage downrange--the slower bullet will catch the faster bullet on the velocity vs. distance curve. Keep in mind, that's all with the bullet's drag curve not changing at all. That said, I would like to see some more detailed numbers showing what triggerfifty described. In fact, I'd like to take back the comparison I made earlier. I should have though about that a bit more before posting. With a 200 [b]fps[/b] advantage at the muzzle, the slower bullet will catch up velocity vs. distance wise (less than 200 fps downrange). But if the muzzle advantage equates to 200 [b]yds[/b], I don't see how the slower bullet will catch up [i]distance[/i]-wise as much as I stated without a serious change to its drag curve. Sure, it could happen. With a 200 yd head start you shouldn't expect [i]exactly[/i] a 200 yd supersonic range advantage...but it should be pretty close unless something odd is happening to the bullet which changes its drag characteristics (overstabilization, not "nosing over" at long ranges, etc). Like I said, it [i]could[/i] happen, but I think it would take a serious change to the bullet's drag curve to do it. If triggerfifty has an explanation of how it happens without, I would be very interested to hear it. [/QUOTE]
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