The gun is a 300rum ,shooting 180gr. ttsx . Sighted in at 200 yards ,say the bullet drops 36" at 500yards on level ground at 2,000 feet elavation. I have a goat at 500yards I am at 2,000 alt, The goat is above me at a 45 degree angle . What would be the drop at that shot? Would you just hold 35 inches high or is there a lot less drop?

You need to get a cosine meter and mount it on your rifle. Then you can take the cosine reading and multiply that with you yardage, or your calculated hold over and it will give you your true hold.

At 500 yards and a 45 degree angle you would need to do the math or use some other means. The load I use would need approximately a 3.75MOA or 16 inch adjustment at 45 degrees verses level at 500 yards.

Because of the angle gravity has far less effect on the drop and thus you would shoot right over the target with that hold. There's a great thread here that can answer all of your questions. http://www.longrangehunting.com/forums/f17/long-range-incline-declined-angle-shots-66782/ At steep angles gravity's effect is mainly on the speed of the bullet rather than it's downward drop and the effect on the speed is all but negligible.

hold for 350y or so. most cell fones have a calculator on them now, just take the cosine of 45deg x 500y to get the sight distance. you dont need all that overpriced cosine indic crap, you otto be able to tell the diff between 15 30 and 45 deg up or down by lookin. hope that helps. everyone. soooo many 'shooters' on this forum and so little TRIG...

I use a simple carpenter's magnetic angle finder that I can easily mount on my small tripod and sight along the bottom edge of the angle finder to my intended target. This gives me my angle, then I match up the angle reading in degrees to the correct cosine on my chart and do the simple math. This can be a little slow, but it's very precise and helps with those first round hits on small targets way out there.