I think .200" is a good choice. I recently had a reamer made for a 6.5mm Wildcat and that is exactly what I ordered for it.
Calculating Free Bore on 6.5 WSM?
- Thread starter BoatTail
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I think .200" is a good choice. I recently had a reamer made for a 6.5mm Wildcat and that is exactly what I ordered for it.
To get a ballpark idea of freebore I do something very simple. It doesn't accurately account for the length of the lead, but I normally just look at a SAAMI spec print to get that close. I go to Berger's bullet spec list. I find the bullet I intend to shoot, look at the bearing surface length. Then subtract the length of the neck from the bearing surface. Whatever is left over I add the lead length to and figure another 0.020-0.030" for Hornady bullets because their bearing surface is almost always a little longer. This is not scientific or perfect, but it gets you a good idea of how much Freebore you need.
Beachnmountains
Member
Agree with all of what is here. .200" FB is a good starter and can always have a good smith throat it more if you don't want to do it yourself. Have no idea why someone would want a high powered 6.5 with freebore in the low .100"s as mentioned in some of the drawings found. Bet that bolt gets very sticky.
David Emerson
Well-Known Member
Depends on how long your box is. Some of these new bullets are very long.
David Emerson
Well-Known Member
I dreamed up a 6.5 x 300 Winchester with some other mods and with a .110 freebore and unconventional throat I am getting 3300 with good pressure in a 26.
David Emerson
Well-Known Member
with a 143 eldx
