Help me figure out how much adjustment this is please. Bulldozer is 120 yards away. Mil value is Half so 1 Mil is really 2. Here it is zeroed out Here is the total adjustment used for shooting 500 yards with the .22lr Also I am not using the scope for this adjustment. it is all in the base. reference Picture, 1 mil= 2 mil I came up with 25 mil So if 25 mil at 120 yards is 108 inches? then 108x 500yards is 540 inches so that's 45 feet of drop? My head hurts now

I don't understand the photos but 25 mil at 500 yards is 450 inches(3.6x5x25). You're correct though that 25 mil at 120 yards is 108 inches(3.6x1.2x25).

From the top to the spot on your second picture it is about 2.5MRAD if the dot distance is 0.2MRAD. 500 yards, that's 500 * 2.5 / 100 = 12.5 yards.

Did you mean CRAD(centiradian), I'm not sure that's a term that is used but it makes sense? MRAD is a milliradian correct?

When someone says mil, usually they mean 0.1 milliradian. It translates to 1/1000 of the distance (1 MRAD is 1/100), in this case 2.5MRAD equals to 500y * 2.5 / 100 = 12.5y.

I don't understand what your asking ? Looks like you are trying to measure the dozer cab window ? Well 108 " is 9 feet, a man sits inside the cab. I would guesstimate the window 4 feet at best. Go measure the window . I believe you need to have your scope set at max power for ranging.

size of target in inches x 27.778 / mil reading = distance to target gun) distance to target / 27.778 x mil reading = size of the target in inchesgun)

Of course. 10cm @ 100m is 1 MRAD which is 1/1000. 1cm@100m is 0.1MRAD. I have no idea what I was thinking last night (nyquil is helluva drug).

In picture 1 at 120 yards you have apporximately 39.8moa from main cross hair to where the crosshair gets fat below the last dot at half value, at full value you have 19.9moa.