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Long Range Hunting & Shooting
Shooting up hill/ Shooting down hill?
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<blockquote data-quote="Michael Eichele" data-source="post: 500316" data-attributes="member: 1007"><p>Let's say for a moment that you are right. The physical path of the bullet is in reality a different measurment compared to shooting at 0 degrees. </p><p></p><p>The point is, if you use this formula, you will make a hit. You have to change the angle of the barrel. The proper way to get the angle right is to apply the principal in the graph. </p><p></p><p>The formulas used to make a 1000 yard hit at 0 degrees dictated how much the rifle's barrel is tilted up. If the bullet drop from bore line is 300" at 1K and you compensate for 300" to make a hit dead on and then shoot 90 degrees straight up at a target the same distance away, you HAVE to undo step by step 100% whatever you just did to compensate for the 0 degree shot. In other words, mathematically you will be 300" high and need to come down 300" to make a hit. 300" up for a level shot, 300" down for a 90 degree shot whether the bullet is 100 or 300" above the target. A 90 degree shot is about angles and getting them all correct, not bullet drop.</p><p></p><p>OR, forget inches for a minute. You compensate 125 clicks in your scope to get the barrel tilted up properly for a 1000 yard 0 degree shot. To make the same shot 90 degrees above you, you have to come back down an equal amount of clicks. That is 125 clicks.</p></blockquote><p></p>
[QUOTE="Michael Eichele, post: 500316, member: 1007"] Let's say for a moment that you are right. The physical path of the bullet is in reality a different measurment compared to shooting at 0 degrees. The point is, if you use this formula, you will make a hit. You have to change the angle of the barrel. The proper way to get the angle right is to apply the principal in the graph. The formulas used to make a 1000 yard hit at 0 degrees dictated how much the rifle's barrel is tilted up. If the bullet drop from bore line is 300" at 1K and you compensate for 300" to make a hit dead on and then shoot 90 degrees straight up at a target the same distance away, you HAVE to undo step by step 100% whatever you just did to compensate for the 0 degree shot. In other words, mathematically you will be 300" high and need to come down 300" to make a hit. 300" up for a level shot, 300" down for a 90 degree shot whether the bullet is 100 or 300" above the target. A 90 degree shot is about angles and getting them all correct, not bullet drop. OR, forget inches for a minute. You compensate 125 clicks in your scope to get the barrel tilted up properly for a 1000 yard 0 degree shot. To make the same shot 90 degrees above you, you have to come back down an equal amount of clicks. That is 125 clicks. [/QUOTE]
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Shooting up hill/ Shooting down hill?
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