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Hunting
Long Range Hunting & Shooting
recoil v accuracy
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<blockquote data-quote="lightwind" data-source="post: 521980" data-attributes="member: 30140"><p><a href="http://www.longrangehunting.com/forums/members/rdm416/" target="_blank">RDM416</a>: Nope. You are thinking of the barrel and bullet as being a closed system. It is not. The law is that force = acceleration*mass. f=m*a. In this case the acceleration is of the bullet and gas through the barrel. The equal and opposite force is against the bolt face. The forces normal to the diameter of the barrel cancel out so there is no sidewise force. The result is that the bolt face is subject to the same backward force as the bullet is forward. The differences in acceleration is due to the differences in the mass. As one of the earlier posters pointed out, that is how recoil operated actions work. If things worked as you say and there was no net force transmitted until the bullet left the barrel the bolt face would not have any force against it because at that point the gas is escaping and pressure is rapidly dropping. So, as the bullet feels the force pushing it forward, there is an equal and opposite force acting on the gun through the bolt face. Think about it for a while and let me know where you think this is wrong. Also think about assuming that this is a closed system when the bullet is moving with only friction and air pressure (external forces) acting on it.</p></blockquote><p></p>
[QUOTE="lightwind, post: 521980, member: 30140"] [URL="http://www.longrangehunting.com/forums/members/rdm416/"]RDM416[/URL]: Nope. You are thinking of the barrel and bullet as being a closed system. It is not. The law is that force = acceleration*mass. f=m*a. In this case the acceleration is of the bullet and gas through the barrel. The equal and opposite force is against the bolt face. The forces normal to the diameter of the barrel cancel out so there is no sidewise force. The result is that the bolt face is subject to the same backward force as the bullet is forward. The differences in acceleration is due to the differences in the mass. As one of the earlier posters pointed out, that is how recoil operated actions work. If things worked as you say and there was no net force transmitted until the bullet left the barrel the bolt face would not have any force against it because at that point the gas is escaping and pressure is rapidly dropping. So, as the bullet feels the force pushing it forward, there is an equal and opposite force acting on the gun through the bolt face. Think about it for a while and let me know where you think this is wrong. Also think about assuming that this is a closed system when the bullet is moving with only friction and air pressure (external forces) acting on it. [/QUOTE]
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