# Line slope calculator 5x-3y=-4

**Straight line given by points A[1; 3] and B[4; 8]**

## Calculation:

**Slope-intercept form of line:**y = 1.6667x+1.3333

**Canonical form of the line equation:**5x-3y+4 = 0

**Parametric form of the line equation:**

x = 3t+1

y = 5t+3 ; t ∈ R

**Slope:**m = 1.6667

**Slope angle of line: φ =**59°2'10″ = 1.0304 rad

**X intercept:**x

_{0}= -0.8

**Y intercept:**y

_{0}= q = 1.3333

**Distance line from the origin:**d

_{0}= 0.686

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(3; 5)

**Normal vector: n =**(5; -3)

**Midpoint of the segment AB: M =**[2.5; 5.5]

**Perpendicular Bisector equation:**3x+5y-35 = 0

**Vector OA = (1; 3) ; |OA| = 3.1623**

**Vector OB = (4; 8) ; |OB| = 8.9443**

**Scalar product OA .OB = 28**

**Angle ∠ AOB = 8°7'48″ = 0.1419 rad**