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<blockquote data-quote="Dave King" data-source="post: 9549" data-attributes="member: 3"><p>Brian</p><p></p><p> I'll get back to you on your addition in a little bit, we still need some work I think.</p><p></p><p> For the 10 mph wind at 500 and stopping at 600 and the target at 1000. You'll need .5 MOA correction as I see it. Here's why, the 100 yards of 10 mph wind will cause 1 MOA of deflection from 500 to 600 yards. This deflection is caused by the projectile adopting an additional sideways motion caused by the wind. This adopted motion does not cease at the 600 yards line when the wind stops, it continues on the same vector, so we have a projectile with a 1 MOA deflection, this equates to 1.047 inches per 100 yards of travel. Add 1.047 inches of deflection for the 600 through 1000 yardsages and your get 5.235 inches of Point Of Impact (POI) to Point Of Aim (POA) error. To figure the amount of correct the shooter needs to correct this ~5" miss we need to turn it into MOA. 5" of error / 10 (for the 1000 yards because MOA is used per 100 yard increments herein)= .5 MOA of correction.</p><p></p><p> Hopefully one of our resident "egg heads" will double check this and chime in if I'm all wet.</p></blockquote><p></p>
[QUOTE="Dave King, post: 9549, member: 3"] Brian I'll get back to you on your addition in a little bit, we still need some work I think. For the 10 mph wind at 500 and stopping at 600 and the target at 1000. You'll need .5 MOA correction as I see it. Here's why, the 100 yards of 10 mph wind will cause 1 MOA of deflection from 500 to 600 yards. This deflection is caused by the projectile adopting an additional sideways motion caused by the wind. This adopted motion does not cease at the 600 yards line when the wind stops, it continues on the same vector, so we have a projectile with a 1 MOA deflection, this equates to 1.047 inches per 100 yards of travel. Add 1.047 inches of deflection for the 600 through 1000 yardsages and your get 5.235 inches of Point Of Impact (POI) to Point Of Aim (POA) error. To figure the amount of correct the shooter needs to correct this ~5" miss we need to turn it into MOA. 5" of error / 10 (for the 1000 yards because MOA is used per 100 yard increments herein)= .5 MOA of correction. Hopefully one of our resident "egg heads" will double check this and chime in if I'm all wet. [/QUOTE]
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