MRAD Elevation issue

[tacomHQ]

Using large whole numbers:
1mil = 40" at 1000
500yd shot = 20"
300yd shot = 12 " (your shot range divided by 1000 times 40 ... (300/1000)*40 = 12)
100yd shot = 4"

That answer minus 10%. 12- 1.2 = 10.8"

500yds= 18"
300yds = 10.8"
100yds = 3.6"

Yep - I know one mil is appr. 36" at 1000yds
36" is 10% less then 40" therefore the 10% is applied to all solutions.
easy whole numbers.

 

[dragon798]

Using large whole numbers:
1mil = 40" at 1000
500yd shot = 20"
300yd shot = 12 " (your shot range divided by 1000 times 40 ... (300/1000)*40 = 12)
100yd shot = 4"

That answer minus 10%. 12- 1.2 = 10.8"

500yds= 18"
300yds = 10.8"
100yds = 3.6"

Yep - I know one mil is appr. 36" at 1000yds
36" is 10% less then 40" therefore the 10% is applied to all solutions.
easy whole numbers.

Actually 1 mil is EXACTLY 36" at 1000yds. It's not an approximate. 1 mil is 1/1000 of any distance. So it's equal to 1" at 1000", 1 meter at 1000 meters, or 1 cubit at 1000 cubits. Too many people attempt to make it difficult, it is not. If you are looking at something 1760 yards away, then 1 mil equals 1.760 yards. As far as drop is concerned, get the inches out of your head. You have a measuring scale 4" in front of your eye; use the reticle and don't try to guesstimate the inches. If the reticle says you are .3mil high and .2mil left, then adjust down .3 and right .2 I totally agree with others on the ballistics app, but you should also get Frank Galli's book, Precision Rifle Marksmanship. His explanation made me a believer in the mil-radian system.

 

[PApa Black]

Hey guys and Gals,
LR newbie here...

My vortex viper 24X50 PST is MRAD and with my 150gr 300 win mag, I have about an 8 inch drop at 300 yards. I am trying to figure out how many clicks on my elevation turret to compensate for the bullet drop. Let's say that there is no wind at the time......

I found a formula somewhere but it didn't look like it would work..

Any help would be appreciated..

I use the Whiz Wheel from Accuracy 1st. No batteries and it's water proof. https://accuracy1st.com/collections/2/Whiz-Wheel-Ballistic-Solvers/

 

[tacomHQ]

Actually 1 mil is EXACTLY 36" at 1000yds. It's not an approximate. 1 mil is 1/1000 of any distance. So it's equal to 1" at 1000", 1 meter at 1000 meters, or 1 cubit at 1000 cubits. Too many people attempt to make it difficult, it is not. If you are looking at something 1760 yards away, then 1 mil equals 1.760 yards. As far as drop is concerned, get the inches out of your head. You have a measuring scale 4" in front of your eye; use the reticle and don't try to guesstimate the inches. If the reticle says you are .3mil high and .2mil left, then adjust down .3 and right .2 I totally agree with others on the ballistics app, but you should also get Frank Galli's book, Precision Rifle Marksmanship. His explanation made me a believer in the mil-radian system.

Sir-- I think the conversation was about a simple conversation how to get to a simple number. I was offering another "language" that is all. Sure the actual best answer is forget moa and inches. Your example of offsetting a shot after one is taken is not, in my mind, what he was asking. The efforts on many of the posted answers was to get to a language and solution he could understand. Let's say I am not as smart as you- I do know that there are approximately 6500 languages spoken - I do not have the ability to communicate with all of those people without a translator. Translators don't start with quantum physics.

Further- "approximate".

0.057295780​

3.437746771​

0.001000000

1.000000000

0.899830217

1.799660435

3.599320869

A calculation for 1mil measured to the 20th decimal place is 3.599320869 inches at 100yds. I am sure the slightest bump can move that but 20places is a few points.
It is not exactly 36".
I use the word "approximate" loosely just to communicate - and approximate for those- like you- who will correct me.
Again this was an exercise in how to communicate with someone who asked for some help.
And as you get ready to key board me to death: I work in sub arc seconds every day. I worked at angstrom levels at a manufacturing level in the late 80's, atomic force, laser, white light interferometry... I have a $40k unit in my assembly room that spends all day measuring arc second values. We build to mil and moa values every day, as in the end, they are an angle. Precision is always a what level.
A starting basic question needs a guidance first. When they are ready they will step forward to the next level of precision as they are willing to take.

 

[Hondo64d]

Hey guys and Gals,
LR newbie here...

My vortex viper 24X50 PST is MRAD and with my 150gr 300 win mag, I have about an 8 inch drop at 300 yards. I am trying to figure out how many clicks on my elevation turret to compensate for the bullet drop. Let's say that there is no wind at the time......

I found a formula somewhere but it didn't look like it would work..

Any help would be appreciated..

I see this question come up a lot lately. If you are converting inches to mils, you are making things much harder on yourself than you need to. Simply measure how far your POI is from the POA using your scope's reticle and adjust accordingly. Here is a play by play on using a scope that has matching reticle and turrets. It is excellent.

How to use that new SWFA scope- reticle, turrets and proper usage.

I have gotten a bunch of requests to write up a "how to" for the SWFA Milquad reticle. It is the 6x42mm SS with MQ reticle in the pictures, however the process and use is the same as long as you have a scope who's reticle matches the turret adjustments- mil/mil or MOA/MO...

www.24hourcampfire.com

John