The sum of first two terms of an infinite G.P. is 5 and each terms is three times the sum of the succeeding terms. Find the G.P.

Hi!

Here is the answer to your question.

Let

*a*be the first term and*r*the common ratio of the infinite G.P.Then,

*a*+*ar*= 5 … (1)*a*= 3(

_{n}*a*

_{n}_{+1 }+

*a*

_{n}_{+2}+

*a*

_{n}_{+3}+ ……..) [By given condition]

⇒

*ar*^{n}^{–1}= 3(*ar*+^{n}*ar*+^{n+1}*ar*+…….)^{n+2}Best Wishes!

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