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What caliber for a sheep rifle?
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<blockquote data-quote="Brown Dog" data-source="post: 125277" data-attributes="member: 1622"><p>[ QUOTE ]</p><p> When a bullet leaves a barrel it drifts at the velocity of the air that it is taveling in. Reguardless of weight, or shape. The distance it drifts is equal to time time velocity (D= T x Vw). </p><p></p><p>[/ QUOTE ] </p><p></p><p>.....well part of the confusion might be arising from the first part of that:</p><p> [ QUOTE ]</p><p> it drifts at the velocity of the air that it is taveling in </p><p></p><p>[/ QUOTE ] ....er, no. It is accelerated by the force exerted on it by the air it is travelling in.....a bullet leaving a muzzle in a 10mph crosswind doesn't immediately go sideways at 10mph!</p><p></p><p>...how fast is it accelerated? Well that will be a function of it's BC. ...but not its 'quoted' BC; because that only quantifies the effect of its shape steadiness etc 'nose-on' .....to be accurate you would have to assess its BC relative to the wind direction (ie for a 90deg wind the bullet is essentially flying sideways) no one would argue that a bullet with a BC of 0.5 would still be a 0.5 BC bullet if it was fired base first; the same is true if it were fired sideways.</p><p></p><p>....so, (and if I'm making no sense here, it's because I'm typing this with a wee bit of a hangover /ubbthreads/images/graemlins/crazy.gif) bjlooper is partly right; the 'nose on' BC is not, strictly speaking, relevant when calculating wind drift (because you would actually need the bullet's 'side on' BC for that particular wind angle).</p><p></p><p>...the fact that the ballistic programs are indicating reduced winddrift due to higher BC is not proof; unless the program in use is 'fudging' an assumed lateral BC based on, say, a calculation involving the BC of a sideways presented 'standard bullet' (they're all essentially similar bullet-diameter tubes when side on) and the actual bullet's nose on BC.</p><p></p><p>.....I would suspect that the empirical 'heavy bullets drift less' observations have much to do with the inertia of the greater mass.</p><p></p><p>Hope I've confused everyone /ubbthreads/images/graemlins/smile.gif /ubbthreads/images/graemlins/confused.gif</p></blockquote><p></p>
[QUOTE="Brown Dog, post: 125277, member: 1622"] [ QUOTE ] When a bullet leaves a barrel it drifts at the velocity of the air that it is taveling in. Reguardless of weight, or shape. The distance it drifts is equal to time time velocity (D= T x Vw). [/ QUOTE ] .....well part of the confusion might be arising from the first part of that: [ QUOTE ] it drifts at the velocity of the air that it is taveling in [/ QUOTE ] ....er, no. It is accelerated by the force exerted on it by the air it is travelling in.....a bullet leaving a muzzle in a 10mph crosswind doesn't immediately go sideways at 10mph! ...how fast is it accelerated? Well that will be a function of it's BC. ...but not its 'quoted' BC; because that only quantifies the effect of its shape steadiness etc 'nose-on' .....to be accurate you would have to assess its BC relative to the wind direction (ie for a 90deg wind the bullet is essentially flying sideways) no one would argue that a bullet with a BC of 0.5 would still be a 0.5 BC bullet if it was fired base first; the same is true if it were fired sideways. ....so, (and if I'm making no sense here, it's because I'm typing this with a wee bit of a hangover [img]/ubbthreads/images/graemlins/crazy.gif[/img]) bjlooper is partly right; the 'nose on' BC is not, strictly speaking, relevant when calculating wind drift (because you would actually need the bullet's 'side on' BC for that particular wind angle). ...the fact that the ballistic programs are indicating reduced winddrift due to higher BC is not proof; unless the program in use is 'fudging' an assumed lateral BC based on, say, a calculation involving the BC of a sideways presented 'standard bullet' (they're all essentially similar bullet-diameter tubes when side on) and the actual bullet's nose on BC. .....I would suspect that the empirical 'heavy bullets drift less' observations have much to do with the inertia of the greater mass. Hope I've confused everyone [img]/ubbthreads/images/graemlins/smile.gif[/img] [img]/ubbthreads/images/graemlins/confused.gif[/img] [/QUOTE]
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