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Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
Shooting on an angle
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<blockquote data-quote="Michael Eichele" data-source="post: 20835" data-attributes="member: 1007"><p>Hey,</p><p></p><p>I am not sure exactly what math you are lookig for but to figure the angles based on a 100 yard zero is difficult. Your use was as follows:</p><p></p><p>"I elect to use the 100 yard 'zero' as the start point for the angle corrected elevation adjustment, I determine the amount of correction required to adjust for the LOS distance and then apply the angle cosine to this value. But, I have a glitch in that my 100 yard 'zero' value is NOT the correct 'zero' for the shot on the current angle problem, in other words, I have no 'zero' reference point for angular trajectories."</p><p></p><p>The only way I have been able to do it is using figures in drop inches from a zero yard zero. In other words, if the rifle was fired perfectly level you would need the inches droped at the range you desire to fire. For instance if you want to fire at a 45 degree angle at 500 yards you first find the level drop in inches and multply that number by the number below. Then deduct that number from your normal bullet drop at 500 yards and fire.</p><p></p><p>5 degrees: Normal bullet drop x .004</p><p>10 degrees: Normal bullet drop x .015</p><p>15 degrees: Normal bullet drop x .034</p><p>20 degrees: Normal bullet drop x .060</p><p>25 degrees: Normal bullet drop x .094</p><p>30 degrees: Normal bullet drop x .134</p><p>35 degrees: Normal bullet drop x .181</p><p>40 degrees: Normal bullet drop x .235</p><p>45 degrees: Normal bullet drop x .293</p><p>50 degrees: Normal bullet drop x .357</p><p>55 degrees: Normal bullet drop x .426</p><p>60 degrees: Normal bullet drop x .500</p><p></p><p>Example: 308 win using a 168 @ 2661 = -36" at 500 yards from a 300 yard zero. real drop= 81" at 500 yards. 81 multiplied by .293=24" Deduct 24 from 36 and you have 13" at 500 yards. Set the scope for 13" and fire.</p><p></p><p>I hope that helps. It maybe somthing you already know. I am not to good at the calculus needed for ballistics. Maybee you can help me??</p><p></p><p>Thanx</p></blockquote><p></p>
[QUOTE="Michael Eichele, post: 20835, member: 1007"] Hey, I am not sure exactly what math you are lookig for but to figure the angles based on a 100 yard zero is difficult. Your use was as follows: "I elect to use the 100 yard 'zero' as the start point for the angle corrected elevation adjustment, I determine the amount of correction required to adjust for the LOS distance and then apply the angle cosine to this value. But, I have a glitch in that my 100 yard 'zero' value is NOT the correct 'zero' for the shot on the current angle problem, in other words, I have no 'zero' reference point for angular trajectories." The only way I have been able to do it is using figures in drop inches from a zero yard zero. In other words, if the rifle was fired perfectly level you would need the inches droped at the range you desire to fire. For instance if you want to fire at a 45 degree angle at 500 yards you first find the level drop in inches and multply that number by the number below. Then deduct that number from your normal bullet drop at 500 yards and fire. 5 degrees: Normal bullet drop x .004 10 degrees: Normal bullet drop x .015 15 degrees: Normal bullet drop x .034 20 degrees: Normal bullet drop x .060 25 degrees: Normal bullet drop x .094 30 degrees: Normal bullet drop x .134 35 degrees: Normal bullet drop x .181 40 degrees: Normal bullet drop x .235 45 degrees: Normal bullet drop x .293 50 degrees: Normal bullet drop x .357 55 degrees: Normal bullet drop x .426 60 degrees: Normal bullet drop x .500 Example: 308 win using a 168 @ 2661 = -36" at 500 yards from a 300 yard zero. real drop= 81" at 500 yards. 81 multiplied by .293=24" Deduct 24 from 36 and you have 13" at 500 yards. Set the scope for 13" and fire. I hope that helps. It maybe somthing you already know. I am not to good at the calculus needed for ballistics. Maybee you can help me?? Thanx [/QUOTE]
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