Forums
New posts
Search forums
What's new
Articles
Latest reviews
Author list
Classifieds
Log in
Register
What's new
Search
Search
Search titles and first posts only
Search titles only
By:
New posts
Search forums
Menu
Log in
Register
Install the app
Install
Forums
Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
Shooting in the Rain?
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Reply to thread
Message
<blockquote data-quote="Buffalobob" data-source="post: 87225" data-attributes="member: 8"><p>Physics is physics- an impapct on the shock wave is an impact on the bullet --by compressing the air that is already compressed you affect the bullet. This is why depth charges destroy submarines, except in reverse.</p><p>Think about it this way. When a bullet hits a deer, does the shock wave protect the bullet from being deformed ? No. The lead tip mushrooms out becuase the mass of the deer impacting on the shock wave pushes the shock wave out of they way. In tissue, a second shock wave arises in the new semi-fluid medium.</p><p></p><p>Vaporizing a drop of water requires how many kcals of enrergy? Check a CRC handbook. Where does that energy come from? Transferring bullet kinetic enregy to heat of vaporization is lost energy which can be computed back to momentum loss which is my point except you have now complicated a simple analysis and you still get the same answer.</p><p></p><p>I could easily be wrong about some of this but two points are valid. My calculations indicate the same thing as you say - in a light rain there is no noticeable effect on bullet drop even at 1000yds.</p><p></p><p>Secondly, the shock wave does not do anything significant regarding the impact except much like in nuclear physics it increases the target radius for the collision. The significant fact is that a raindrop does not weigh much and is traveling slow so the impact is trivial.</p></blockquote><p></p>
[QUOTE="Buffalobob, post: 87225, member: 8"] Physics is physics- an impapct on the shock wave is an impact on the bullet --by compressing the air that is already compressed you affect the bullet. This is why depth charges destroy submarines, except in reverse. Think about it this way. When a bullet hits a deer, does the shock wave protect the bullet from being deformed ? No. The lead tip mushrooms out becuase the mass of the deer impacting on the shock wave pushes the shock wave out of they way. In tissue, a second shock wave arises in the new semi-fluid medium. Vaporizing a drop of water requires how many kcals of enrergy? Check a CRC handbook. Where does that energy come from? Transferring bullet kinetic enregy to heat of vaporization is lost energy which can be computed back to momentum loss which is my point except you have now complicated a simple analysis and you still get the same answer. I could easily be wrong about some of this but two points are valid. My calculations indicate the same thing as you say - in a light rain there is no noticeable effect on bullet drop even at 1000yds. Secondly, the shock wave does not do anything significant regarding the impact except much like in nuclear physics it increases the target radius for the collision. The significant fact is that a raindrop does not weigh much and is traveling slow so the impact is trivial. [/QUOTE]
Insert quotes…
Verification
Post reply
Forums
Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
Shooting in the Rain?
Top