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Rifles, Reloading, Optics, Equipment
Reloading
Revisiting: sorting cases by weight
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<blockquote data-quote="ntsqd" data-source="post: 1651511" data-attributes="member: 93138"><p>I think maybe my thought train isn't getting across. I'll try it differently. For the sake of discussion I'm letting the case exterior dims be exactly the same as the chamber and assuming no spring-back. I'm also assuming that the metal density does not change within one case, that it that the density is the same through-out the whole case. the first assumption is to simplify the process of thinking this thru. The second is a reasonable assumption for all metals in smaller volumes.</p><p></p><p>I see the chamber as a fixed volume. Assuming that the density of the case metal is the same from case to case then it doesn't matter where within each case that metal is distributed, it occupies the same volume if the cases weigh the same. That metal volume is subtractive from the chamber volume and the result is the total case volume.</p><p></p><p>Said a little differently, if the metal density and the case weight is the same but the distribution within the cases is different then they should still hold the same weight of water.</p><p></p><p>Unless I'm missing something.</p></blockquote><p></p>
[QUOTE="ntsqd, post: 1651511, member: 93138"] I think maybe my thought train isn't getting across. I'll try it differently. For the sake of discussion I'm letting the case exterior dims be exactly the same as the chamber and assuming no spring-back. I'm also assuming that the metal density does not change within one case, that it that the density is the same through-out the whole case. the first assumption is to simplify the process of thinking this thru. The second is a reasonable assumption for all metals in smaller volumes. I see the chamber as a fixed volume. Assuming that the density of the case metal is the same from case to case then it doesn't matter where within each case that metal is distributed, it occupies the same volume if the cases weigh the same. That metal volume is subtractive from the chamber volume and the result is the total case volume. Said a little differently, if the metal density and the case weight is the same but the distribution within the cases is different then they should still hold the same weight of water. Unless I'm missing something. [/QUOTE]
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Rifles, Reloading, Optics, Equipment
Reloading
Revisiting: sorting cases by weight
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