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Rifles, Reloading, Optics, Equipment
Long Range Scopes and Other Optics
MOA to MIL - did you switch?
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<blockquote data-quote="dfanonymous" data-source="post: 1770522" data-attributes="member: 97050"><p>No, Todd Hodnetts wind formula is good, just does not account for elevation changes and you have to jump your BC constant to account for velocity bleed off. Honestly it's probably good enough for most.</p><p></p><p>What I'm talking about is similar to what you are talking about probably. how I know it is calculating your 90 degree wind and determining at what mph is equal to .5 at 500y or 1 mil at 1000.</p><p>So if you have a wind of 8 mph = 1 mil at 1000y that should leave table looking like .2 at 200 .6 at 600 and so on with an 8 mph wind. So my 16 mph wind at 600 would be 1.2 my 4 mph wind is at 600 is .3 etc. add .1 for spin and so forth.</p><p>You can do wind angles and such for a 16 mph wind at half value, you take the 1.2 then divide by 2 in example.</p></blockquote><p></p>
[QUOTE="dfanonymous, post: 1770522, member: 97050"] No, Todd Hodnetts wind formula is good, just does not account for elevation changes and you have to jump your BC constant to account for velocity bleed off. Honestly it’s probably good enough for most. What I’m talking about is similar to what you are talking about probably. how I know it is calculating your 90 degree wind and determining at what mph is equal to .5 at 500y or 1 mil at 1000. So if you have a wind of 8 mph = 1 mil at 1000y that should leave table looking like .2 at 200 .6 at 600 and so on with an 8 mph wind. So my 16 mph wind at 600 would be 1.2 my 4 mph wind is at 600 is .3 etc. add .1 for spin and so forth. You can do wind angles and such for a 16 mph wind at half value, you take the 1.2 then divide by 2 in example. [/QUOTE]
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Rifles, Reloading, Optics, Equipment
Long Range Scopes and Other Optics
MOA to MIL - did you switch?
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