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Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
Litz's Description of Coriolis.
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<blockquote data-quote="Michael Eichele" data-source="post: 909813" data-attributes="member: 1007"><p>Think of it this way:</p><p></p><p>You're 100 yards from a road. Your rifle is pointed at the road at car level. A car drives from your right to the left at 60 MPH. When the car is in your crosshairs you pull the trigger. Do you hit the car?</p><p></p><p>No.</p><p></p><p>Where did the bullet go? The builet went straight but the car moved out of its way. OR, impacted to the right of the car.</p><p></p><p>Can you picture that? Cool.</p><p></p><p>Now, rewind, imagine a passenger in that same car that you're about to shoot at. He has a rifle sticking out the window. When his crosshairs align with you, he pulls the trigger. Does he hit you? </p><p></p><p>No. Why? </p><p></p><p>Because you (the target) have been stationary. The bullet fired at you is moving laterally at 60 MPH and therefore impacts to the??? You guessed it. The right of you from the passengers perspective. </p><p></p><p>You fired and hit right from your perspective and he fired and hit right from his perspective. </p><p></p><p>When you sit on the North Pole and fire at a target on the equator, it's like you're shooting from a stationary position at a moving target. </p><p></p><p>When you sit on the equator and fire at a target at the North Pole, you're the passenger in the moving car shooting at a stationary target.</p><p></p><p>Now I understand that you're not taking shots to or from the equator to or from the poles but it does illustrate the principal. The point is that the rotational velocity is greater south of your position no matter where you are in the northern hemisphere at least to the point when you meet up with the equator.</p><p></p><p>If you sit 500 yards north of the equator and shoot at a target 500 yards south of the equator the correction is minimal. Why? Because your target and yourself both have the same rotational velocity, or surface velocity as Michael Courtney put it.</p></blockquote><p></p>
[QUOTE="Michael Eichele, post: 909813, member: 1007"] Think of it this way: You're 100 yards from a road. Your rifle is pointed at the road at car level. A car drives from your right to the left at 60 MPH. When the car is in your crosshairs you pull the trigger. Do you hit the car? No. Where did the bullet go? The builet went straight but the car moved out of its way. OR, impacted to the right of the car. Can you picture that? Cool. Now, rewind, imagine a passenger in that same car that you're about to shoot at. He has a rifle sticking out the window. When his crosshairs align with you, he pulls the trigger. Does he hit you? No. Why? Because you (the target) have been stationary. The bullet fired at you is moving laterally at 60 MPH and therefore impacts to the??? You guessed it. The right of you from the passengers perspective. You fired and hit right from your perspective and he fired and hit right from his perspective. When you sit on the North Pole and fire at a target on the equator, it's like you're shooting from a stationary position at a moving target. When you sit on the equator and fire at a target at the North Pole, you're the passenger in the moving car shooting at a stationary target. Now I understand that you're not taking shots to or from the equator to or from the poles but it does illustrate the principal. The point is that the rotational velocity is greater south of your position no matter where you are in the northern hemisphere at least to the point when you meet up with the equator. If you sit 500 yards north of the equator and shoot at a target 500 yards south of the equator the correction is minimal. Why? Because your target and yourself both have the same rotational velocity, or surface velocity as Michael Courtney put it. [/QUOTE]
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Litz's Description of Coriolis.
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