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Gravity effects on bullets
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<blockquote data-quote="del2les" data-source="post: 2975053" data-attributes="member: 9299"><p>F = G * m1 * m2 / d^2</p><p>g = G * m earth / (d earth)^2</p><p>W = m * g[/center]</p><p></p><p>Since the gravitational constant (g) depends on the square of the distance from the center of the earth, we would expect that the weight of an object would decrease with altitude. Let's do a test problem to see how much the weight changes. If an airplane is flying at 35,000 feet (about 7 miles) the distance to the center of the earth is about 4,007 miles. We can calculate the change in the gravitational constant as the square of (4000/4007) which equals .9965. If the airplane weighs 10,000 pounds on the surface of the earth, it weighs 9,965 pounds at 35,000 feet; it has lost 35 pounds, a very small amount compared to 10,000 pounds.</p></blockquote><p></p>
[QUOTE="del2les, post: 2975053, member: 9299"] F = G * m1 * m2 / d^2 g = G * m earth / (d earth)^2 W = m * g[/center] Since the gravitational constant (g) depends on the square of the distance from the center of the earth, we would expect that the weight of an object would decrease with altitude. Let's do a test problem to see how much the weight changes. If an airplane is flying at 35,000 feet (about 7 miles) the distance to the center of the earth is about 4,007 miles. We can calculate the change in the gravitational constant as the square of (4000/4007) which equals .9965. If the airplane weighs 10,000 pounds on the surface of the earth, it weighs 9,965 pounds at 35,000 feet; it has lost 35 pounds, a very small amount compared to 10,000 pounds. [/QUOTE]
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