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Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
Coriolis effect
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<blockquote data-quote="Blaine Fields" data-source="post: 29311" data-attributes="member: 183"><p>According to Prof. Pejsa ("Modern Practical Ballistics") and Robert McCoy ("Modern Exterior Ballistics") the following describes lateral deflection resulting from a turning earth (i.e., the Coriolis effect):</p><p></p><p>Deflection = (K*R^2*sin L)/V where K is a constant, R is the range, L is the latitude and V is the average velocity over the range R.</p><p></p><p>According to McCoy, all deflections are to the right in the Northern hemisphere and math-wise the formula presented will not change in sign.</p><p></p><p>Intuitively this is hard to accept. Hence, my post: does anyone have a source to the contrary?</p></blockquote><p></p>
[QUOTE="Blaine Fields, post: 29311, member: 183"] According to Prof. Pejsa ("Modern Practical Ballistics") and Robert McCoy ("Modern Exterior Ballistics") the following describes lateral deflection resulting from a turning earth (i.e., the Coriolis effect): Deflection = (K*R^2*sin L)/V where K is a constant, R is the range, L is the latitude and V is the average velocity over the range R. According to McCoy, all deflections are to the right in the Northern hemisphere and math-wise the formula presented will not change in sign. Intuitively this is hard to accept. Hence, my post: does anyone have a source to the contrary? [/QUOTE]
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Coriolis effect
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