Forums
New posts
Search forums
What's new
Articles
Latest reviews
Author list
Classifieds
Log in
Register
What's new
Search
Search
Search titles and first posts only
Search titles only
By:
New posts
Search forums
Menu
Log in
Register
Install the app
Install
Forums
Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
Canting formula
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Reply to thread
Message
<blockquote data-quote="Bart B" data-source="post: 108370" data-attributes="member: 5302"><p>Hey, Gustavo, my wife spent a couple of nights in Buenos Aires a couple of years ago on her way to Ushuaia near Cape Horn. Beautiful city, she said and really neat and nice people!!!!</p><p></p><p>This cant stuff is a simple situation. I've been dealing with it for years.</p><p></p><p>Example: at 1000 yards, bullet drop is 350 inches and the cant angle is 1 degree. </p><p></p><p>Horizontal impact change due to cant is equal to bullet drop at target range multiplied by the sine of the angle. Sine of 1 degree is 0.01745, that times 350 equals 6.11 inches horizontal impact change.</p><p></p><p>Vertical impact change equals bullet drop minus the cosine of the angle multiplied by the bullet drop. Cosine of 1 degree is 0.99985, that times 350 equals 349.95 inches, and 350 minus 349.95 equals .05 inches below the horizontal where the bullet would strike.</p><p></p><p>Horizontal change is the worst problem. Even with a 10 degree cant in the above example, the bullet would strike about 60 inches to the side but only about 5 inches low. Sight height above the bore doesn't matter.</p></blockquote><p></p>
[QUOTE="Bart B, post: 108370, member: 5302"] Hey, Gustavo, my wife spent a couple of nights in Buenos Aires a couple of years ago on her way to Ushuaia near Cape Horn. Beautiful city, she said and really neat and nice people!!!! This cant stuff is a simple situation. I've been dealing with it for years. Example: at 1000 yards, bullet drop is 350 inches and the cant angle is 1 degree. Horizontal impact change due to cant is equal to bullet drop at target range multiplied by the sine of the angle. Sine of 1 degree is 0.01745, that times 350 equals 6.11 inches horizontal impact change. Vertical impact change equals bullet drop minus the cosine of the angle multiplied by the bullet drop. Cosine of 1 degree is 0.99985, that times 350 equals 349.95 inches, and 350 minus 349.95 equals .05 inches below the horizontal where the bullet would strike. Horizontal change is the worst problem. Even with a 10 degree cant in the above example, the bullet would strike about 60 inches to the side but only about 5 inches low. Sight height above the bore doesn't matter. [/QUOTE]
Insert quotes…
Verification
Post reply
Forums
Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
Canting formula
Top