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Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
Bullet stabilization, strictly RPM?
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<blockquote data-quote="X-man" data-source="post: 170518" data-attributes="member: 8416"><p><strong>Blacko</strong></p><p>I too have learned a great deal here.</p><p>Thanks to those that make this a great site!</p><p></p><p><strong>DWM</strong></p><p>You got me thinking about this rotational killing power stuff!</p><p>I don't know how to calculate the energy of a rotating object, but here is what I tried based on the outside velocity of Mikecr's 140 grain .284 bullet at 254K rpms.</p><p></p><p>Diameter (.284) X 3.143 (pye)= 0.893 inches (traveled per revolution) </p><p>0.893 X 4233 revs/second (254K/60) = 3780 inches traveled/second = <strong>315 </strong>feet traveled per second.</p><p></p><p>While a 140 grain bullet traveling at 315 fps produces <strong>30.9 fpe</strong> (not much) I can't see how a rotating mass could generate any more than this.</p><p></p><p>As near as my pea brain can tell my calculations give credit to the entire 140 grains at the outside edge of the projectile (the center portion of the bullet is rotating slower than the outside edge). Which leads me to believe (in my pea brain) that the actual energy figure is less than I have calculated???</p><p></p><p>There must be someone smarter than me that can make some sense of this, but according to my figures rotational bullet energy should have almost no effect on killing power???</p><p></p><p></p><p>Now my head hurts......Help!!???</p></blockquote><p></p>
[QUOTE="X-man, post: 170518, member: 8416"] [B]Blacko[/B] I too have learned a great deal here. Thanks to those that make this a great site! [B]DWM[/B] You got me thinking about this rotational killing power stuff! I don't know how to calculate the energy of a rotating object, but here is what I tried based on the outside velocity of Mikecr's 140 grain .284 bullet at 254K rpms. Diameter (.284) X 3.143 (pye)= 0.893 inches (traveled per revolution) 0.893 X 4233 revs/second (254K/60) = 3780 inches traveled/second = [B]315 [/B]feet traveled per second. While a 140 grain bullet traveling at 315 fps produces [B]30.9 fpe[/B] (not much) I can't see how a rotating mass could generate any more than this. As near as my pea brain can tell my calculations give credit to the entire 140 grains at the outside edge of the projectile (the center portion of the bullet is rotating slower than the outside edge). Which leads me to believe (in my pea brain) that the actual energy figure is less than I have calculated??? There must be someone smarter than me that can make some sense of this, but according to my figures rotational bullet energy should have almost no effect on killing power??? Now my head hurts......Help!!??? [/QUOTE]
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Rifles, Reloading, Optics, Equipment
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Bullet stabilization, strictly RPM?
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