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Applied Ballistics For Long Range Shooting By Bryan Litz
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<blockquote data-quote="Russ Hatch" data-source="post: 304482" data-attributes="member: 12444"><p>"According to the principles of bullet dispersion given in Chapter 11, we can extrapolate the group size from 100 yards to 500 yards based on the bullets time of flight. The bullets time of flight at 100 yards is 0.1084 seconds, and at 500 yards, it's 0.6154 seconds. Since the rifle is capable of grouping into 1 inch at 100 yards, we can expect the dispersion to produce a 500 yard group of: 1 inch times 0.6154/0.1084 = 5.7 inches minimum."</p><p> </p><p>The way I under stand it is if you are thinking that the dispersion is angular,(I.E. one inch at 100yds would give you five inches at 500yds or 10 inches at 1000yds), its not angular but is related to the bullets time of flight. Sort of like which area of wind is most important at the muzzle or at the target. At least that is part of what I got from chapter 11 of the book. By no means am I an expert on any of this. Hope this helps. Maybe Bryan will chime in.</p><p>Russ</p></blockquote><p></p>
[QUOTE="Russ Hatch, post: 304482, member: 12444"] "According to the principles of bullet dispersion given in Chapter 11, we can extrapolate the group size from 100 yards to 500 yards based on the bullets time of flight. The bullets time of flight at 100 yards is 0.1084 seconds, and at 500 yards, it’s 0.6154 seconds. Since the rifle is capable of grouping into 1 inch at 100 yards, we can expect the dispersion to produce a 500 yard group of: 1 inch times 0.6154/0.1084 = 5.7 inches minimum." The way I under stand it is if you are thinking that the dispersion is angular,(I.E. one inch at 100yds would give you five inches at 500yds or 10 inches at 1000yds), its not angular but is related to the bullets time of flight. Sort of like which area of wind is most important at the muzzle or at the target. At least that is part of what I got from chapter 11 of the book. By no means am I an expert on any of this. Hope this helps. Maybe Bryan will chime in. Russ [/QUOTE]
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