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Rifles, Reloading, Optics, Equipment
Rifles, Bullets, Barrels & Ballistics
A new spin drift and coriolis question (I think) Exbal
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<blockquote data-quote="noel carlson" data-source="post: 278050" data-attributes="member: 16138"><p>JMason,</p><p> </p><p>AJ is correct, in that as long as you do not change test latitude to any significant degree, there is no practical need to distinguish the two effects. They are essentially constants relative to horizontal shift.</p><p> </p><p>If you wanted to separate the components empirically (for the fun of it<img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite1" alt=":)" title="Smile :)" loading="lazy" data-shortname=":)" />), reverse barrel twist, and get a statistically meaningful sample of gauging hits from the two barrrels at range.</p><p> </p><p>The median offset, from an optically established center, equals the coriolis deflection.</p></blockquote><p></p>
[QUOTE="noel carlson, post: 278050, member: 16138"] JMason, AJ is correct, in that as long as you do not change test latitude to any significant degree, there is no practical need to distinguish the two effects. They are essentially constants relative to horizontal shift. If you wanted to separate the components empirically (for the fun of it:)), reverse barrel twist, and get a statistically meaningful sample of gauging hits from the two barrrels at range. The median offset, from an optically established center, equals the coriolis deflection. [/QUOTE]
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Rifles, Reloading, Optics, Equipment
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A new spin drift and coriolis question (I think) Exbal
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