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logic fault?

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  #1  
Unread 06-17-2011, 12:38 PM
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logic fault?

So here I am on the side of a steep slope, it is 900 yds. down to target level and the target is 900 yds. in front of me. The bullet I am useing goes subsonic at 1,050 yrds. my conclusion is that the target is 222yds. out of range for me. Whats your conclusion?
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  •   #2  
    Unread 06-20-2011, 09:42 PM
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    Re: logic fault?

    So would that be a 45 degree downhill shot? A little confused. what did the range finder and ADI say?
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      #3  
    Unread 06-20-2011, 10:29 PM
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    Re: logic fault?

    Quote:
    Originally Posted by ken snyder View Post
    So here I am on the side of a steep slope, it is 900 yds. down to target level and the target is 900 yds. in front of me. The bullet I am useing goes subsonic at 1,050 yrds. my conclusion is that the target is 222yds. out of range for me. Whats your conclusion?
    Accepting that a target is out of range when it is farther than your bullet's ability to remain supersonic, then yes, you are correct.

    A2 + B2 = C2

    A = Opposite
    B = Adjacent
    C = Hypotenuse



    In this case:

    9002 + 9002 = C2

    810,000 + 810,000 = 1,620,000

    √1,620,000 = ~1,272
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      #4  
    Unread 06-22-2011, 11:53 PM
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    Re: logic fault?

    Quote:
    Originally Posted by ken snyder View Post
    So here I am on the side of a steep slope, it is 900 yds. down to target level and the target is 900 yds. in front of me. The bullet I am useing goes subsonic at 1,050 yrds. my conclusion is that the target is 222yds. out of range for me. Whats your conclusion?

    Your math is correct, assuming a 45 degree angle. I think in reality, if you are hunting game, the maximun range is usually far less than the subsonic speed would indicate. Most hunting bullets aren't designed for proper expansion and performance at that low of a velocity.........Just passing on a thought.
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    Last edited by SBruce; 06-23-2011 at 02:42 AM.
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      #5  
    Unread 06-23-2011, 08:55 AM
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    Re: logic fault?

    As Trebark said and demonstrated with his drawing, you are correct. One thing I think gets missed when we are talking long range shots at steep angles is: THE SHOT IS STILL THE FULL UNCORRECTED DISTANCE. The angle only effects the distance gravity has a downward pull on the bullet. So, when the rangefinder says 1200 yards, and the angle corrected dial up is 950......... just remember it is still a 1200 yard shot. Wind, and other environmental factors have to be calculated at 1200, not 950 in that example.
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      #6  
    Unread 06-23-2011, 09:57 AM
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    Re: logic fault?

    Thanks guys. My buddy was having a hard time understanding that and needed to read it from someone other than myself. I picked the numbers for simplicity. Why 900 horizontal yards is possible and a calculated 900 + yd hold is different.
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      #7  
    Unread 06-23-2011, 10:37 AM
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    Re: logic fault?

    It should also be said that this calculation is true regardless of wether the shot is up-hill or down-hill.

    Also, looks like some of the formatting was lost from my first post. A2 = A(squared) or in this case:

    900x900 + 900x900 = C(squared)

    810,000 + 810,000 = 1,620,000

    square root of...1,620,000 = ~1,272
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