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logic fault?

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#1
06-17-2011, 01:38 PM
 Silver Member Join Date: Jul 2010 Posts: 420
logic fault?

So here I am on the side of a steep slope, it is 900 yds. down to target level and the target is 900 yds. in front of me. The bullet I am useing goes subsonic at 1,050 yrds. my conclusion is that the target is 222yds. out of range for me. Whats your conclusion?
#2
06-20-2011, 10:42 PM
 Silver Member Join Date: Mar 2010 Location: Spring, TX Posts: 345
Re: logic fault?

So would that be a 45 degree downhill shot? A little confused. what did the range finder and ADI say?
#3
06-20-2011, 11:29 PM
 Platinum Member Join Date: Jan 2008 Location: Falls Church, VA Posts: 3,045
Re: logic fault?

Quote:
 Originally Posted by ken snyder So here I am on the side of a steep slope, it is 900 yds. down to target level and the target is 900 yds. in front of me. The bullet I am useing goes subsonic at 1,050 yrds. my conclusion is that the target is 222yds. out of range for me. Whats your conclusion?
Accepting that a target is out of range when it is farther than your bullet's ability to remain supersonic, then yes, you are correct.

A2 + B2 = C2

A = Opposite
B = Adjacent
C = Hypotenuse

In this case:

9002 + 9002 = C2

810,000 + 810,000 = 1,620,000

√1,620,000 = ~1,272
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#4
06-23-2011, 12:53 AM
 Platinum Member Join Date: Oct 2009 Location: Thunder Basin, WY Posts: 1,787
Re: logic fault?

Quote:
 Originally Posted by ken snyder So here I am on the side of a steep slope, it is 900 yds. down to target level and the target is 900 yds. in front of me. The bullet I am useing goes subsonic at 1,050 yrds. my conclusion is that the target is 222yds. out of range for me. Whats your conclusion?

Your math is correct, assuming a 45 degree angle. I think in reality, if you are hunting game, the maximun range is usually far less than the subsonic speed would indicate. Most hunting bullets aren't designed for proper expansion and performance at that low of a velocity.........Just passing on a thought.
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SBruce

Last edited by SBruce; 06-23-2011 at 03:42 AM..
#5
06-23-2011, 09:55 AM
 Gold Member Join Date: Jan 2005 Location: Searcy, Arkansas Posts: 700
Re: logic fault?

As Trebark said and demonstrated with his drawing, you are correct. One thing I think gets missed when we are talking long range shots at steep angles is: THE SHOT IS STILL THE FULL UNCORRECTED DISTANCE. The angle only effects the distance gravity has a downward pull on the bullet. So, when the rangefinder says 1200 yards, and the angle corrected dial up is 950......... just remember it is still a 1200 yard shot. Wind, and other environmental factors have to be calculated at 1200, not 950 in that example.
#6
06-23-2011, 10:57 AM
 Silver Member Join Date: Jul 2010 Posts: 420
Re: logic fault?

Thanks guys. My buddy was having a hard time understanding that and needed to read it from someone other than myself. I picked the numbers for simplicity. Why 900 horizontal yards is possible and a calculated 900 + yd hold is different.
#7
06-23-2011, 11:37 AM
 Platinum Member Join Date: Jan 2008 Location: Falls Church, VA Posts: 3,045
Re: logic fault?

It should also be said that this calculation is true regardless of wether the shot is up-hill or down-hill.

Also, looks like some of the formatting was lost from my first post. A2 = A(squared) or in this case:

900x900 + 900x900 = C(squared)

810,000 + 810,000 = 1,620,000

square root of...1,620,000 = ~1,272
__________________
I'm not gonna shoot here. I'm gonna shoot waaaaaaaay over there!

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