Originally Posted by jwp475
I opened up the link from your post and here's what I found >>>
Fc = 2MΩV sin(Θ)
Where: Fc = Coriolis force in the horizontal
M = Mass of the object
Ω = Angular velocity of the Earth (360 degrees per 24 hours)
V = Velocity of the object over the surface of the Earth
Θ = Latitude in degrees
The Coriolis force acts at a right angle to the direction of motion of the object. It pushes the object to the right in the Northern hemisphere and to the left in the Southern.
This article restricted itself to the discussion of horizontal Coriolis forces. I'm an engineer by training and practice, I've had a buttload of mathematics, and I can tell you that this mathematical equation doesn't include any input factor in order to account for direction (azimuth) of fire. In addition, the Notes: under the equation state that Coriolis pushes objects to the right in the Northern hemisphere and left in the Southern.
The notes don't state that the force only exists on objects travelling north or south. Patagonia Ballistic's Loadbase 2.0 software program output shows horizontal Coriolis drift to be the same no matter the direction of fire for a given latitude
. I would think someone would have pointed out the error in their program a long time ago if there was one. Until someone provides a sound reference for their theory that horizontal Coriolis drift is only present when shooting north or south, and that it's completely absent when shooting exactly east (90 degree azimuth) or west (270 degree azimuth), I'll have to continue to believe my Loadbase 2.0 software output.